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seen Jan 18 at 18:32

Dec
23
awarded  Caucus
Sep
9
revised Prove that the limit exists and then find its limit
added 12 characters in body
Sep
9
answered Prove that the limit exists and then find its limit
Jul
29
awarded  Yearling
Jul
2
awarded  Curious
Apr
28
comment real analysis on function continuity and rational numbers
Every subset of $Z$ is open. If you consider $Z$ as a metric space with $d(x,y)=|x-y|$ then $\{1\} = \{x : d(x,1) < 1/2 \}$.
Apr
27
answered real analysis on function continuity and rational numbers
Apr
1
revised Measurable function remaining constant
fixed typo
Feb
10
accepted Uniform convergence in a neighborhood of zero.
Feb
10
asked Uniform convergence in a neighborhood of zero.
Jan
3
awarded  Tumbleweed
Nov
19
revised Asymptotic behaviour of $a_{k+1}=a_{k}(1+\frac{1}{\log a_{k}})$
added 2501 characters in body
Nov
19
revised Asymptotic behaviour of $a_{k+1}=a_{k}(1+\frac{1}{\log a_{k}})$
added 664 characters in body
Nov
19
revised Optimally combining samples to estimate averages
fixed wrong coefficients
Nov
19
comment Asymptotic behaviour of $a_{k+1}=a_{k}(1+\frac{1}{\log a_{k}})$
You are correct, I missed that.
Nov
19
revised Asymptotic behaviour of $a_{k+1}=a_{k}(1+\frac{1}{\log a_{k}})$
edited body
Nov
19
comment Asymptotic behaviour of $a_{k+1}=a_{k}(1+\frac{1}{\log a_{k}})$
$a_k \sim b_k $ does not imply $\exp a_k \sim \exp b_k$ example $ a_k = k $ and $b_k = k + \ln k$.
Nov
19
answered Asymptotic behaviour of $a_{k+1}=a_{k}(1+\frac{1}{\log a_{k}})$
Nov
18
revised Optimally combining samples to estimate averages
typo : wrong superscript
Nov
18
comment Optimally combining samples to estimate averages
@triomphe : Jens talked about the Normal case, but the same answer holds for a larger set of distributions as long as we restrict ourselves to linear combinations of the measurements.