Reputation
6,892
Top tag
Next privilege 10,000 Rep.
Access moderator tools
Badges
1 7 17
Newest
 Caucus
Impact
~89k people reached

10h
reviewed Approve How do I calculate $ \int_{1}^{3} x/(2-x) \;\mathrm{d}x$
10h
reviewed Approve The Definition of Consistency and Compactness in FOL
10h
reviewed Approve Calculating flux for a triangle
1d
comment Show that the following sequence converges for $ 0 < a < e $ and diverges for $ a \ge e$
Try to find the radius of convergence as $R = \lim\limits_{n\to\infty} \left| \dfrac{c_n}{c_{n+1}} \right|,$ where $c_n=\dfrac{n!}{n^n}.$
1d
reviewed Approve Error in a Maclaurin series
May
23
reviewed Approve Show that the set $\{1,2,\ldots, n-1\}$ is a group under $\bmod n$ IFF $n$ is prime.
May
21
comment what is the value of 0^0?
Zero to the zero power
May
18
reviewed Approve limits-without-lhospital tag wiki excerpt
May
10
reviewed Approve How can the number $\left\langle \matrix {3&3\\3&3}\right\rangle $ be described?
May
9
reviewed Approve Find points in which grad(f)(x,y) = 0
May
9
reviewed Approve Why is $(e_n)$ not a basis for $\ell_\infty$?
May
9
reviewed Approve Find the area of a surface of revolution about the y-axis $x=\frac{y^3}{3}$ for $-2\leq y \leq 2$
May
9
reviewed Approve Distribution of transformed poisson distribution
May
5
reviewed Approve What does this question about classifying the states of this Markov chain mean?
May
1
reviewed Approve What is category theory?
Apr
25
comment Test $\sum\limits_{n=1}^{\infty} \frac{(-1)^n\ln(n)}{n}$ for convergence
Note that $\frac{1}{n^2}(1-\ln(n))<0\ $ for all $n \geqslant{3}$ and rejection of a finite number of terms does not affect the convergence
Apr
21
reviewed Approve Find minimal $x$ and $y$ that creates $4$
Apr
17
reviewed Approve Can dx be equal to dy?
Apr
11
comment Integral of trig fraction using substitution
You can check your integration by differentiating the answer $\sqrt{1+2\sin{x}}+c$
Apr
10
comment evaluating some limits - calculus
Use L'Hôpital's rule to prove that $\lim\limits_{t\to+\infty}\dfrac{e^t}{\ln{t}}=+\infty.$