network profile
| bio | website | |
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| location | ||
| age | ||
| visits | member for | 8 months |
| seen | Sep 19 '12 at 9:10 | |
| stats | profile views | 5 |
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Sep 17 |
awarded | Supporter |
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Sep 14 |
comment |
Integrating $\int_0^{500}e^{\frac{(x-a)^2}{b^2}} dx$ Thanks for your detailed description of \Phi . I have been having trouble understanding how to use it and the most of the descriptions I have found about it go over my head slightly. I think I have a better idea of what to do now. |
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Sep 14 |
revised |
Integrating $\int_0^{500}e^{\frac{(x-a)^2}{b^2}} dx$ added 2 characters in body |
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Sep 14 |
comment |
Integrating $\int_0^{500}e^{\frac{(x-a)^2}{b^2}} dx$ There should indeed be a minus sign. The reason I omitted much of the detail is because I thought I could get a general understanding of the issue at hand and then apply it to my problem but it seems this issue is far more complex than I estimated. |
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Sep 14 |
comment |
Integrating $\int_0^{500}e^{\frac{(x-a)^2}{b^2}} dx$ Thanks again vanna. I thought maybe there was a way to calculate it, but if not then I will look more carefully into using a cdf. |
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Sep 14 |
awarded | Editor |
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Sep 14 |
comment |
Integrating $\int_0^{500}e^{\frac{(x-a)^2}{b^2}} dx$ Ooops forgot those. . Edited |
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Sep 14 |
revised |
Integrating $\int_0^{500}e^{\frac{(x-a)^2}{b^2}} dx$ added 16 characters in body |
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Sep 14 |
awarded | Student |
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Sep 14 |
asked | Integrating $\int_0^{500}e^{\frac{(x-a)^2}{b^2}} dx$ |
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Sep 14 |
awarded | Scholar |
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Sep 14 |
accepted | Transforming a Continuous Function |
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Sep 14 |
comment |
Transforming a Continuous Function This is helping me greatly. Thank you. Could you recommend any reading material on normalizing functions. I am particularly interested in how you managed to calculate $$ y(x) = \frac{1}{\phi\left(\frac{500-d}{c}\right)-\phi\left(\frac{-d}{c}\right)}\frac{1}{c\sqrt{2\pi}}e^{-\frac{1}{2}\frac{(x-d)^2}{c^2}} 1_{\{0\le x \le 500\}}$$ |
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Sep 14 |
comment |
Transforming a Continuous Function Yes you right. My mistake. I just copied the formula directly without thinking. |
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Sep 14 |
comment |
Transforming a Continuous Function So if I calculate: $y(x) = \frac{1}{\int_0^500 b + \frac{a}{c\sqrt{\frac{\pi}{2}}} \cdot e^{\frac{-2(u-d)^{2}}{c^{2}}} du} \cdot (b + \frac{a}{c\sqrt{\frac{\pi}{2}}} \cdot e^{\frac{-2(x-d)^{2}}{c^{2}}})$ I can normalize the function yes? Also since the integral is between 0 and 500 that means that my x values will be bounded? Final question does this mean that I will be able to change the standard deviation and still maintain a curve with an approximately consistent area below the curve? Thank you very much for your clear and concise answer |
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Sep 14 |
asked | Transforming a Continuous Function |
