meta user
network profile
| bio | website | |
|---|---|---|
| location | ||
| age | ||
| visits | member for | 9 months |
| seen | Jan 11 at 3:43 | |
| stats | profile views | 7 |
I'm a math/computer science student. I'm here to learn just as much as I am to help others learn.
|
Dec 17 |
comment |
Inverse function of $y=\frac{\ln(x+1)}{\ln x}$ @macydanim: It's not quite that simple. $\exp(\log(x)y) \neq x\exp(y)$. Instead, $\exp(\log(x)y) = x^y$. |
|
Dec 15 |
comment |
Precalculus word problem on rocket height Are you sure you didn't forget a minus sign in $H(t)$? $H(t) = -8t^2 + 32t$ looks like it would be more reasonable. |
|
Dec 15 |
revised |
Determine $K$ and find the density functions of the random variables $Z = \max(X,Y)$ and $T = \min(X, Y )$. minor clarification |
|
Dec 15 |
answered | Determine $K$ and find the density functions of the random variables $Z = \max(X,Y)$ and $T = \min(X, Y )$. |
|
Dec 15 |
revised |
Find the smallest possible value of $a_1$. minor/LaTeX |
|
Dec 15 |
revised |
Find the smallest possible value of $a_1$. improved LaTeX style |
|
Dec 15 |
revised |
Find the smallest possible value of $a_1$. improved LaTeX style |
|
Dec 15 |
revised |
Find the smallest possible value of $a_1$. wording made more correct |
|
Dec 15 |
revised |
Find the smallest possible value of $a_1$. additional explanation |
|
Dec 15 |
answered | Find the smallest possible value of $a_1$. |
|
Dec 12 |
awarded | Supporter |
|
Dec 11 |
awarded | Analytical |
|
Dec 11 |
awarded | Editor |
|
Dec 11 |
revised |
Why isn't $\log(-1)=i\pi$? added 2 characters in body |
|
Dec 11 |
awarded | Teacher |
|
Dec 11 |
answered | Why isn't $\log(-1)=i\pi$? |
|
Sep 14 |
comment |
Finding probability of other child also being a boy @kabirkukreti: Because the two children are different. This is not necessarily intuitive, so I'll attempt to illustrate my point a similar example. Suppose you flip a fair coin twice. There are four possible (equally likely) outcomes: HH, HT, TT, TH. TH and HT are different because of the order in which the heads and tails appeared. The first coin flip has a 1/2 chance of landing either way, and the second flip, because it is completely independent of the first, also has a 1/2 chance of going either way. While not immediately obvious, this is also the case for the B/G problem. |
|
Sep 14 |
comment |
Finding probability of other child also being a boy @emory: We can assume that each of the two children has a 1/2 chance of being either gender (1/2 chance of being boy, 1/2 chance of being girl). There is a 1/2 chance that the first child is a boy. If the first child is a boy, then there is a 1/2 chance that the second child is either gender. By multiplication rule, this leaves a 1/4 chance for BB and a 1/4 chance for BG (1/2 $\times$ 1/2 = 1/4). Similar logic can be used to yield a 1/4 chance for GB and GG each. |
|
Sep 13 |
answered | Finding probability of other child also being a boy |
