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Jun
24
comment Solution to quadratic question of the form 0/0
You should add an answer to the question "where is the catch", meaning, where in OP's argumentation is the error.
Apr
27
awarded  Critic
Mar
31
asked Standard Deviation divided by Mean
Feb
4
awarded  Nice Question
Jan
20
comment Reason for LCM of all numbers from 1 .. n equals roughly $e^n$
Not as simple as I hoped for, but I managed. And furthermore I think it won't get much simpler than that.
Jan
20
accepted Reason for LCM of all numbers from 1 .. n equals roughly $e^n$
Jan
20
revised Reason for LCM of all numbers from 1 .. n equals roughly $e^n$
plot fix
Jan
20
asked Reason for LCM of all numbers from 1 .. n equals roughly $e^n$
Sep
30
awarded  Explainer
Sep
12
awarded  Yearling
Dec
9
accepted Is it valid to write $\displaystyle \lim_{x \to 0} \frac{1}{x^2} = \infty$?
Dec
9
comment Is it valid to write $\displaystyle \lim_{x \to 0} \frac{1}{x^2} = \infty$?
Just for completeness: What about $\lim_{x \to 0} \frac{1}{x} = ±\infty$?
Dec
9
comment Is it valid to write $\displaystyle \lim_{x \to 0} \frac{1}{x^2} = \infty$?
That $+\infty$ thing is interesting. Does it mean that $\infty$ without the $+$ can mean positive as well as negative? In particular, can one write $\lim_{x \to 0} \frac{1}{x} = \infty$ even if that can be positive or negative?
Dec
9
comment Is it valid to write $\displaystyle \lim_{x \to 0} \frac{1}{x^2} = \infty$?
No problem, since I'm not so fluent in English mathematics, questions like these point out things to me I didn't know yet. So the case here with limes vs. limit. Thanks to @Daniel Fischer. :)
Dec
9
comment Is it valid to write $\displaystyle \lim_{x \to 0} \frac{1}{x^2} = \infty$?
No …? Your question baffles me.
Dec
9
asked Is it valid to write $\displaystyle \lim_{x \to 0} \frac{1}{x^2} = \infty$?
Dec
4
awarded  Scholar
Dec
4
accepted Non-iterative solution for $(a + nb)\mod c < d$
Dec
4
accepted How to solve $y = \frac{1}{x-1} +\frac {1}{x-5}$ for $x$
Dec
4
comment How to solve $y = \frac{1}{x-1} +\frac {1}{x-5}$ for $x$
Right. Thanks a lot, now it seems too simple ;-) (will accept as soon as possible).