| bio | website | |
|---|---|---|
| location | Erie, PA | |
| age | 25 | |
| visits | member for | 8 months |
| seen | Feb 20 at 16:37 | |
| stats | profile views | 6 |
I am a programmer that is currently finishing up a bachelors degree in computer science.
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Sep 15 |
comment |
Proving a factorial is not a certain complexity I would believe that the series would only increase by one. Since the limit itself is the node going to infinity there is really no change for n+1. n+1 will still basically be a very large number as it approaches infinity. |
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Sep 15 |
awarded | Scholar |
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Sep 15 |
comment |
Calculating Average Case Complexity That was a good answer and very easy to follow. I feel that I can now solve a case complexity problem for a series that has several conditions. Basically it is a matter of defining the problem space. Matching conditions and then making a final deductive step. |
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Sep 15 |
accepted | Calculating Average Case Complexity |
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Sep 15 |
awarded | Supporter |
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Sep 15 |
comment |
Proving a factorial is not a certain complexity @Steven Stadnicki Do you have any good resources that can help me remove my confusion on this? I must say that my algorithms teacher is not making it very clear and my discrete teacher decided to gloss over the subject as well. So bascially in the CS side of my classes, we all just put the two together so it is hard to separate. |
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Sep 14 |
asked | Proving a factorial is not a certain complexity |
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Sep 14 |
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Algorithmic Complexity of $i^2$ How can I deal with a more general function for this problem. Like proving for the general case that $$\sum_{i=1}^n i^k is O(n^{k-1})$$ |
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Sep 14 |
asked | Prove a formula is corect |
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Sep 14 |
asked | Calculating Average Case Complexity |
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Sep 11 |
awarded | Commentator |
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Sep 11 |
comment |
Algorithmic Complexity of $i^2$ Still not quite sure how you got this. I can see that you took the general i case and said that it was less than or equal to the n max case. But how you determined because of that the complexity is $O(n^{3})$ baffles me. |
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Sep 11 |
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Algorithmic Complexity of $i^2$ @StevenStadnicki Sorry, the computer science student in me is trying to make since of it all. This means creating relations that are not there. |
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Sep 11 |
awarded | Editor |
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Sep 11 |
comment |
If $f(n) = \sum_{i = 0}^n X_{i}$, then show by induction that $f(n) = f(n - 1) + X_{n-1}$ I have mistakenly given you the wrong equation. |
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Sep 11 |
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If $f(n) = \sum_{i = 0}^n X_{i}$, then show by induction that $f(n) = f(n - 1) + X_{n-1}$ I had mistakenly given you the wrong equation. |
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Sep 11 |
revised |
If $f(n) = \sum_{i = 0}^n X_{i}$, then show by induction that $f(n) = f(n - 1) + X_{n-1}$ added 232 characters in body |
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Sep 11 |
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If $f(n) = \sum_{i = 0}^n X_{i}$, then show by induction that $f(n) = f(n - 1) + X_{n-1}$ @BillDubuque Thank you, I will take a look. I wish I knew what was really expected in this course as well. I would be all for proving and showing if an algorithm is correct or not if my professor actually knew what was going on. Most of the time its just him trying to solve his own lecture problem (which doesn't help much with strategy.) |
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Sep 11 |
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If $f(n) = \sum_{i = 0}^n X_{i}$, then show by induction that $f(n) = f(n - 1) + X_{n-1}$ @BillDubuque This is a class on algorithms and data structures. We are using Introduction to Algorithms 3rd edition. My professor is what many would call very very unclear on explaining how to derive and solve these algorithms and I fear that teaching myself is making me only more confused. |
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Sep 11 |
awarded | Student |