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Mar
13
revised 3-fold connected covers of punctured torus
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Mar
11
revised 3-fold connected covers of punctured torus
edited tags
Mar
11
revised 3-fold connected covers of punctured torus
added 94 characters in body
Mar
11
asked 3-fold connected covers of punctured torus
Feb
20
awarded  Teacher
Oct
9
asked Vector bundle addition
Sep
10
awarded  Yearling
May
1
comment Function that cannot be extended continuously out of sphere
Thanks. I wasn't actually interested in S^n itself but had in my mind a general compact subset hence I did not give much thought to the (obvious) solution above.
May
1
accepted Function that cannot be extended continuously out of sphere
May
1
asked Function that cannot be extended continuously out of sphere
Mar
18
accepted Showing an analytic map has closed irreducible image
Mar
17
comment Showing an analytic map has closed irreducible image
If we define variety as integral separated scheme of finite type (here over $\mathbb C$) isn't it Hausdorff then?
Mar
17
comment Showing an analytic map has closed irreducible image
Isn't it true that $Y$ is necessarily Hausdorff since it is a variety? I think this follows from the requirement that it should be separated, but am not 100% sure. Do you have a reference for why this is true if $Y$ is Hausdorff?
Mar
17
revised Showing an analytic map has closed irreducible image
added 136 characters in body
Mar
16
revised Showing an analytic map has closed irreducible image
added 236 characters in body
Mar
16
comment Showing an analytic map has closed irreducible image
Wait a minute. Sorry to "unaccept" the answer, but your map $g$ hence $\tilde g$ is $analytic$, and your argument seems to treat it like an algebraic map, unless I am hugely missing something here...
Mar
16
comment Showing an analytic map has closed irreducible image
Ok, that makes sense. Thanks a lot!
Mar
15
comment Showing an analytic map has closed irreducible image
That $X$ may be covered by affine open sets $Spec(B)$ such that each $\pi^{-1}(SpecB)$ is covered by finitely many affine open sets $Spec(A)$ where $A$ is finitely generated $B$-algebra.
Mar
15
comment Showing an analytic map has closed irreducible image
You claim $\pi$ is quasi-finite; ie it has finite fibers (true by hypothesis) and is of finite type. Why is the latter true?
Mar
15
comment Showing an analytic map has closed irreducible image
Don't you need $\pi$ to be finite for it to be quasi-finite? And also, why is the dimension the same?