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Sep 15 '12 at 21:56
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Solving inequality $\frac{2x}{x-2}>1$
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Simplify $\ln(|x-x^2|) - \ln(|x-1|)$
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Simplifying expression with absolute value and unknown
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Simplify $\ln(|x-x^2|) - \ln(|x-1|)$
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Solving inequality $\frac{2x}{x-2}>1$
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