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Apr
3
comment A Conjecture based on the Complex Conjugate Root Theorem.
I agree, I was just thinking aloud
Apr
3
comment A Conjecture based on the Complex Conjugate Root Theorem.
so you can get polynomials of degree n with n prescribed roots...
Apr
3
comment A Conjecture based on the Complex Conjugate Root Theorem.
every monic polynomial f(z) is the product of $z-\alpha_k$, where $\alpha_k$ are its roots.
Mar
5
comment On Hyper-geometric Functions and its recurrence relation
right, just replace $a$ by $a+n$
Mar
5
comment On Hyper-geometric Functions and its recurrence relation
$a$ is just a parameter; nothing will become invalid if you change it to $a+n$.
Feb
25
comment Eigenvalues of Symmetric Pseudo-Toeplitz Matrix
I suppose you checked en.wikipedia.org/wiki/Tridiagonal_matrix#Determinant and noticed that due to this, you can write down the characteristic polynomial quickly.
Nov
8
awarded  Autobiographer
Apr
5
comment Dominated convergence theorem and fundamental lemma
this looks like a meaningful question...
Mar
27
awarded  Commentator
Mar
27
awarded  Yearling
Mar
26
comment Proving that $(e^x+1)^{1/3}$ has no elementary antiderivative
well, consider my answer being done by computer, not me :-)
Mar
26
answered Proving that $(e^x+1)^{1/3}$ has no elementary antiderivative
Mar
22
comment Determinant of a Vandermonde matrix of roots of monic polynomial with integer coefficients
the square of the Vandermonde is a symmetric function, and thus Per's argument applies.
Mar
18
comment Nauty software package and weighted graphs
There is no such command in dreadnaut. You will have to supply it the already prepared non-weighted graph.
Mar
18
comment Nauty software package and weighted graphs
Well, how you represent weights is an entirely different question. In the setting of computing automorphisms and isomorphisms all what matters is that different weights are represented by different integer numbers (or colours).
Mar
18
answered Nauty software package and weighted graphs
Feb
12
revised Ten dimensional representation of $S_6$
expanded...
Feb
11
answered Ten dimensional representation of $S_6$
Jan
21
comment How unitarize an irreducible representation of a finite group?
In fact you don't need to compute eigenvalues and eigenvectors. Although you will still need to compute square roots of real cyclotomics at the end, as I mentioned in GAP forum.
Dec
19
awarded  Caucus