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  • 142 votes cast
Mar
30
comment Find linear equation given single y value and the gradient
@Dhruv I see you tried to edit my answer, but in the process the $ sign dropped off from $65 per hour. If you are going to make changes, please ensure units are removed in the process.
Mar
30
comment Find linear equation given single y value and the gradient
@KobeyRafferty Thanks Bro
Mar
30
comment Find linear equation given single y value and the gradient
@KobeyRafferty, gradient = rise/run. We are given two coordinates (3 hours, 220) and (7 hours, 480). Rise = 480 - 220 and Run = 7-3 = 4. Does this make sense?
Mar
30
comment Generate all N-bit numbers in such an order that the number of 1s increases monotonically
Define efficient
Aug
28
comment How to calculate the limit of $(\frac{x}{x+1})^x$
Thanks. It appears therefore that in a fair casino game, provided you only play one session (of x games) in your lifetime, you will come out on top 63% of the time. Even if the casino has an edge, you can come out on top (that is when z > 1 but z< 1.44). I believe this is most applicable to the lottery where you are only likely to play one session in your lifetime.
Aug
28
comment How to calculate the limit of $(\frac{x}{x+1})^x$
I apologize for the downvote and to make up for it I have upvoted and awarded you the best answer. Thanks very much!
Aug
28
comment How to calculate the limit of $(\frac{x}{x+1})^x$
thanks I look forward to seeing the full answer and awarding it as best.
Aug
28
comment How to calculate the limit of $(\frac{x}{x+1})^x$
@RecklessReckoner, yeah i accidentally displayed 1- (1/e) which is 0.632, I will edit to correct.
Aug
28
comment How to calculate the limit of $(\frac{x}{x+1})^x$
This answer doesn't acknowledge the second part of my question at all involving the z.
Jul
11
comment How to calculate CI for percentage difference?
the percentage increase was normally distributed so I figure it is safe to use the standard T-test. Good to know that this isn't a huge violation of statistics.
Jul
11
comment How to calculate CI for percentage difference?
Thanks very much Bruce, very helpful.
Jul
3
comment Two different samples from different time periods.
@RossMillikan, I'm not assuming normal distribution. I just calculated mean by adding up numbers and dividing by n. I calculated standard devation by finding average distance between squares of numbers. I haven't made any assumptions about the distribution though.
Jul
3
comment Two different samples from different time periods.
@Feyre, does credibility theory apply here?en.wikipedia.org/wiki/Credibility_theory
Jul
3
comment Two different samples from different time periods.
@Feyre, just a thought experiment I invented myself. I welcome the most technical answers.
Jul
3
comment Two different samples from different time periods.
For the sake of simplicity, I want to assume that all conditions are the same for the students, except the period of time is separated by 1 year. Now I agree the samples are statistically different, but the 1st sample had a much greater sample size, and thus might still have some weight on my future prediction, as the most recent sample could be an anomoly.
Jun
14
comment What are some simple (or elegant) functions that satisfy these conditions?
@Crostul, that looks good - how can I adjust how "flat" it is?
Apr
21
comment Distribution Function Of a Random Variable X - Question
@SuperRhinocerus, what are you studying?
Apr
20
comment A store is offering a 20% discount on a certain item. The store’s sale of the item is subject to a 6% sales tax.
no problem glad to have helped :)
Apr
20
comment A store is offering a 20% discount on a certain item. The store’s sale of the item is subject to a 6% sales tax.
correct, the pure tax component itself is 0.06*0.8x, and thus the total amount including tax is 1.06*0.8x, whereas scenario 1 is 0.8*1.06x, which is equal.
Apr
18
comment Find the height of statue.
@ClaudeLeibovici, yes my assumption was that the height of the observer was insignificant compared to the height of the tower, however without knowing the angles X and Y the validity of this assumption is still in the dark.