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  • 0 posts edited
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  • 136 votes cast
Aug
28
comment How to calculate the limit of $(\frac{x}{x+1})^x$
Thanks. It appears therefore that in a fair casino game, provided you only play one session (of x games) in your lifetime, you will come out on top 63% of the time. Even if the casino has an edge, you can come out on top (that is when z > 1 but z< 1.44). I believe this is most applicable to the lottery where you are only likely to play one session in your lifetime.
Aug
28
comment How to calculate the limit of $(\frac{x}{x+1})^x$
I apologize for the downvote and to make up for it I have upvoted and awarded you the best answer. Thanks very much!
Aug
28
accepted How to calculate the limit of $(\frac{x}{x+1})^x$
Aug
28
comment How to calculate the limit of $(\frac{x}{x+1})^x$
thanks I look forward to seeing the full answer and awarding it as best.
Aug
28
revised How to calculate the limit of $(\frac{x}{x+1})^x$
edited body
Aug
28
comment How to calculate the limit of $(\frac{x}{x+1})^x$
@RecklessReckoner, yeah i accidentally displayed 1- (1/e) which is 0.632, I will edit to correct.
Aug
28
comment How to calculate the limit of $(\frac{x}{x+1})^x$
This answer doesn't acknowledge the second part of my question at all involving the z.
Aug
28
revised How to calculate the limit of $(\frac{x}{x+1})^x$
deleted 4 characters in body
Aug
28
revised How to calculate the limit of $(\frac{x}{x+1})^x$
added 172 characters in body
Aug
28
asked How to calculate the limit of $(\frac{x}{x+1})^x$
Jul
11
comment How to calculate CI for percentage difference?
the percentage increase was normally distributed so I figure it is safe to use the standard T-test. Good to know that this isn't a huge violation of statistics.
Jul
11
comment How to calculate CI for percentage difference?
Thanks very much Bruce, very helpful.
Jul
11
accepted How to calculate CI for percentage difference?
Jul
10
asked How to calculate CI for percentage difference?
Jul
3
comment Two different samples from different time periods.
@RossMillikan, I'm not assuming normal distribution. I just calculated mean by adding up numbers and dividing by n. I calculated standard devation by finding average distance between squares of numbers. I haven't made any assumptions about the distribution though.
Jul
3
comment Two different samples from different time periods.
@Feyre, does credibility theory apply here?en.wikipedia.org/wiki/Credibility_theory
Jul
3
comment Two different samples from different time periods.
@Feyre, just a thought experiment I invented myself. I welcome the most technical answers.
Jul
3
comment Two different samples from different time periods.
For the sake of simplicity, I want to assume that all conditions are the same for the students, except the period of time is separated by 1 year. Now I agree the samples are statistically different, but the 1st sample had a much greater sample size, and thus might still have some weight on my future prediction, as the most recent sample could be an anomoly.
Jul
3
asked Two different samples from different time periods.
Jun
14
comment Probability of tossing 16 coins.
Because the results in (a) aren't significantly different from 0.5 (expected for a coin), it seems they have used 0.5 as the probability in calculating b. Remember the probability of tails isn't 0.4625, but rather this is your estimate of the probability. Most likely the probability is still just 0.5 (can confirm with confidence intervals, p values etc.)