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comment Integral $\int_2^4 \sqrt{16-x^2} \operatorname d\!x $
Yes, the solution manual did it in this way too, but I couldn't come up with it myself.
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asked Integral $\int_2^4 \sqrt{16-x^2} \operatorname d\!x $
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comment Sum notation confusion
But what is the purpose of the $i$ in there, then?
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asked Why is the derivative of the arccos the negative derivative of arcsin?
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