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seen Oct 9 at 8:23

Oct
9
comment Integral $\int_2^4 \sqrt{16-x^2} \operatorname d\!x $
Yes, the solution manual did it in this way too, but I couldn't come up with it myself.
Oct
9
asked Integral $\int_2^4 \sqrt{16-x^2} \operatorname d\!x $
Oct
9
comment Sum notation confusion
But what is the purpose of the $i$ in there, then?
Oct
9
asked Sum notation confusion
Oct
9
asked Why is the derivative of the arccos the negative derivative of arcsin?
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