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Mar
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comment How would I put these recurrence relation terms into a summation?
Oh I see... this would only work if the numerator was $1$ because $1$ raised to any power is $1$. If the numerator wasn't a $1$, I wouldn't be able to do this trick right?
Mar
3
comment How would I put these recurrence relation terms into a summation?
I'm a little confused on how you got $(1/2)^{i}$ from $2^{-i}$. I thought this was only true if the numerator was also raised to the same power?
Mar
3
comment How would I put these recurrence relation terms into a summation?
@GerryMyerson I have edited the question with what I have tried and what I am getting stuck on.
Mar
3
revised How would I put these recurrence relation terms into a summation?
added more work
Mar
3
comment How would I put these recurrence relation terms into a summation?
Yes, I know that trick but it didn't help me in this case. I'm not sure if I set up the summation correctly. It seems to make sense but I have no idea how to sum it up because it isn't in a form with a known formula.
Mar
3
reviewed Approve How would I put these recurrence relation terms into a summation?
Mar
3
asked How would I put these recurrence relation terms into a summation?
Mar
3
accepted Is there a formula for the summation of this form?
Mar
3
comment Is there a formula for the summation of this form?
I didn't even think about simplifying the expression... Thank you for the help!
Mar
3
asked Is there a formula for the summation of this form?
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Oct
19
accepted Finding the probability using probability distributions.