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comment How would I put these recurrence relation terms into a summation?
Oh I see... this would only work if the numerator was $1$ because $1$ raised to any power is $1$. If the numerator wasn't a $1$, I wouldn't be able to do this trick right?
Mar
3
comment How would I put these recurrence relation terms into a summation?
I'm a little confused on how you got $(1/2)^{i}$ from $2^{-i}$. I thought this was only true if the numerator was also raised to the same power?
Mar
3
comment How would I put these recurrence relation terms into a summation?
@GerryMyerson I have edited the question with what I have tried and what I am getting stuck on.
Mar
3
revised How would I put these recurrence relation terms into a summation?
added more work