network profile
| bio | website | |
|---|---|---|
| location | New Delhi | |
| age | 21 | |
| visits | member for | 8 months |
| seen | Apr 19 at 13:18 | |
| stats | profile views | 7 |
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Apr 15 |
comment |
XOR of Binary Numbers to Reach a Given Number Thank You! That was really helpful :) I was able to implement the algorithm in C++ based on your input. |
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Apr 14 |
revised |
XOR of Binary Numbers to Reach a Given Number added 278 characters in body |
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Apr 14 |
comment |
XOR of Binary Numbers to Reach a Given Number I tried reducing the matrix to a row echelon form. But with the modulo 2 arithmetic operations, the row echelon form seems to be unreachable. (eg) if the set S = {0010, 1001, 1010, 0101, 1110, 1100 } and X = {0001}, how do I follow the reduction procedure ? I have to develop a c++ implementation for a 1000x200 matrix. |
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Apr 14 |
accepted | XOR of Binary Numbers to Reach a Given Number |
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Apr 14 |
comment |
XOR of Binary Numbers to Reach a Given Number Thank You! Can I get a reference link on how to find whether the augmented matrix is solvable ? The size of the set S can be upto 1000. I just need to find whether a solution exists or not. |
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Apr 14 |
asked | XOR of Binary Numbers to Reach a Given Number |
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Mar 20 |
awarded | Supporter |
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Mar 20 |
accepted | Sum up to number $N$ using $1,2$ and $3$ |
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Mar 19 |
asked | Sum up to number $N$ using $1,2$ and $3$ |
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Oct 2 |
accepted | How to find the Circular permutation with Repetition |
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Oct 2 |
comment |
How to find the Circular permutation with Repetition Thanks , got it.. |
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Oct 2 |
asked | How to find the Circular permutation with Repetition |
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Sep 7 |
awarded | Student |
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Sep 7 |
comment |
How to remove the denominator? @KarolisJuodelė Understood. Got the solution now :) |
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Sep 7 |
awarded | Scholar |
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Sep 7 |
accepted | How to remove the denominator? |
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Sep 7 |
revised |
How to remove the denominator? Corrected the equation. A + sign instead of a - sign |
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Sep 7 |
revised |
How to remove the denominator? added 334 characters in body |
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Sep 7 |
comment |
How to remove the denominator? @DrKW : Sorry there must be a typo. This expression is a reduced form of another expression. Must have made a typo in that. The value for n=9 is 1332. |
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Sep 7 |
comment |
How to remove the denominator? @Sasha : The values are only for n>3 |
