Reputation
33,929
Next tag badge:
84/100 score
11/20 answers
Badges
9 49 135
Newest
 Nice Answer
Impact
~261k people reached

3h
comment Fair and Unfair coin Probability
You claim that the problem is with $P($either one of the tosses is heads on the two coins$)$. You need to calculate the probability of there being precisely one occurrence of a head in the tossing of the second coin. In your calculation, you subtracted the probability of no heads from one. The remaining probability covers one head or both heads, but you want to exclude the latter. If you make this adjustment, you will get the correct answer.
4h
comment Getting the formula of a line when given $2$ points
The correct equation should be $y = 7x$ (note that the point $(1, 7)$ doesn't lie on the line $y = -\frac{1}{7}x$).
21h
revised Is there a relationship between the existence of parallel vectors on two planes, and their line of intersection.
edited tags
22h
revised Why is the closedness of the set on which $f = g$ immediate, when proving the Identity Theorem?
added 8 characters in body; edited title
22h
revised Why is the closedness of the set on which $f = g$ immediate, when proving the Identity Theorem?
added 37 characters in body
22h
answered Why is the closedness of the set on which $f = g$ immediate, when proving the Identity Theorem?
22h
reviewed Looks OK Show that $A$ is open in $\mathbb R$
1d
comment Limit comparison test how to choose $b_n$?
I think you want the $n$ above the sum to be $\infty$.
1d
revised What is the modern approach to tensors?
added 124 characters in body
1d
answered What is the modern approach to tensors?
1d
revised If $a,b,x,y\in\Bbb N$ , and $ax-by=(a,b)$, then $(x,y)=1$
edited tags
1d
asked Is there an analogue of Eilenberg-Maclane spaces for homology?
1d
comment Subgroup of group is normal
@xhimi: $X$ if $Y$ means $Y \implies X$ whereas $X$ only if $Y$ means $X \implies Y$. What you claimed is that a subgroup is normal only if the group is abelian (i.e. subgroup is normal $\implies$ abelian), but this is false as I pointed out. What is true is that the a subgroup is normal if the group is abelian (i.e. abelain $\implies$ subgroup is normal).
1d
awarded  Nice Answer
1d
revised In a non-Hausdorff space, can a compact subset fail to be closed?
deleted 5 characters in body
1d
reviewed Reopen Question about Measure Theory
1d
comment Exercise of Analysis in ℝn
Welcome to math.SE. In order to get the best possible answers, it is helpful if you say in what context you encountered the problem, and what your thoughts on it are; this will prevent people from telling you things you already know, and help them give their answers at the right level.
1d
answered Complex inner product linearity
1d
comment John b.Conway chapter $2$ section $2$ exercise $4$
Welcome to math.SE. In order to get the best possible answers, it is helpful if you say in what context you encountered the problem, and what your thoughts on it are; this will prevent people from telling you things you already know, and help them give their answers at the right level.
1d
comment Is $\ker(\operatorname{nat}_H)=H$?
So the context is that $G$ is a group with normal subgroup $H$ and $\operatorname{nat}_H : G \to G/H$ is the homomorphism $g \mapsto gH$.