23,485 reputation
63074
bio website
location Adelaide, Australia
age 25
visits member for 1 year, 11 months
seen 10 hours ago

Taking a break for a while.


11h
reviewed Looks OK How do I multiply $2(\frac{4}{y})$?
11h
reviewed Close Using Direct Proof. $1+2+3+\ldots+n = \frac{n(n + 1)}{2}$
11h
reviewed Looks OK How do I multiply $2(\frac{4}{y})$?
11h
reviewed Leave Closed manipulation of internal hom
11h
reviewed Reopen Co-ordinate system transformation of Complex Numbers
11h
reviewed Reopen Define a parametrized curve $\beta:(a,b)\rightarrow\mathbb R^3$ by $\beta(t)=\frac{d\gamma(t)}{dt}$
13h
reviewed Leave Closed The sum of the $n$ smallest odd numbers is equal to $n^2$
14h
reviewed Leave Closed metric spaces and topology
21h
reviewed Leave Closed Where is the missing rupee?
1d
reviewed Edit Find $g(x)$ if $(x^2+a^2)(x^2 + b^2)(x^2 + c^2) = (f(x))^2 + (g(x))^2$ and $f(x)$ is a degree three polynomial
1d
revised Find $g(x)$ if $(x^2+a^2)(x^2 + b^2)(x^2 + c^2) = (f(x))^2 + (g(x))^2$ and $f(x)$ is a degree three polynomial
deleted 12 characters in body; edited title
1d
reviewed Approve suggested edit on hint with an exercise algebra
1d
reviewed Approve suggested edit on A question on classification of real numbers.
1d
comment If $G/K\cong H/K$ must $G\cong H$?
@ThomasAndrews: I am aware of that, but it wasn't clear to me that the OP was.
1d
comment If $G/K\cong H/K$ must $G\cong H$?
Do you mean that $G$ and $H$ both contain $K$, or do you mean that $G$ contains a normal subgroup which is isomorphic to a normal subgroup of $H$, namely $K$?
1d
accepted Can we measure how close a vector bundle is to being trivial?
1d
revised Integral inequality: $\def\intd{\,\mathrm d}\int_a^b(f'(x))^2\intd x-2\big(f(a)+f(b)\big)^2\geq\frac8{(b-a)^2}\int_a^b(f(x))^2\intd x$
edited title
1d
reviewed Approve suggested edit on Integral inequality: $\def\intd{\,\mathrm d}\int_a^b(f'(x))^2\intd x-2\big(f(a)+f(b)\big)^2\geq\frac8{(b-a)^2}\int_a^b(f(x))^2\intd x$
1d
reviewed Delete normally distributed
1d
reviewed Delete How to show that $\mathbb R^n$ is an open set?