| bio | website | |
|---|---|---|
| location | ||
| age | 17 | |
| visits | member for | 8 months |
| seen | 11 hours ago | |
| stats | profile views | 116 |
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Apr 6 |
answered | The limit of a recurrence relation (with resistors) |
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Apr 6 |
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The limit of a recurrence relation (with resistors) Thanks for that. Is $\large \lim _{n \rightarrow \infty}(\frac{F_{n+1}r^2+F_n rR}{F_{n-1}R^2+F_n r})$ computable directly? |
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Apr 6 |
revised |
The limit of a recurrence relation (with resistors) added 3 characters in body |
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Apr 6 |
revised |
The limit of a recurrence relation (with resistors) added 269 characters in body |
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Apr 6 |
asked | The limit of a recurrence relation (with resistors) |
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Apr 2 |
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What's the proof that the Euler totient function is multiplicative? Thank you- at long last it's clicked! |
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Apr 2 |
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Best Fake Proofs? (A M.SE April Fools Day collection) @spin the L'Hopital's one may be worth posting. |
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Apr 2 |
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Best Fake Proofs? (A M.SE April Fools Day collection) Really' you've proven that girls are absolutely evil. |
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Apr 2 |
answered | Interpret the equation $2x^2+3=4x+y$ geometrically |
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Apr 1 |
awarded | Good Answer |
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Apr 1 |
awarded | Nice Answer |
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Apr 1 |
answered | Best Fake Proofs? (A M.SE April Fools Day collection) |
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Mar 31 |
revised |
How to solve $x!=5^x$? edited tags |
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Mar 28 |
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Algebraic equation problem - finding $x$ komal.hu/verseny/… This really shouldn't be up here for a couple of weeks. |
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Mar 23 |
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Functions satisfying $f(m+f(n)) = f(m) + n$ @DejanGovc Thanks; that's really quite elegant. |
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Mar 23 |
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Functions satisfying $f(m+f(n)) = f(m) + n$ @DejanGovc, could you explain why the usual argument claims $f(x)=cx$ is the only class of solutions to the rational Cauchy's functional equation? |
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Mar 10 |
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Intuition behind $\nabla \times \mathbf{F}$ Thanks for your patience! I thought it was the dot product (perhaps add that to the answer in case dullards like myself might benefit from it). |
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Mar 10 |
accepted | Intuition behind $\nabla \times \mathbf{F}$ |
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Mar 10 |
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Intuition behind $\nabla \times \mathbf{F}$ Why not just evaluate $(\nabla \times \mathbf{F})(x_0,y_0,z_0)$? |
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Mar 10 |
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Intuition behind $\nabla \times \mathbf{F}$ Excellent answer (as far as I can tell), by the way. |