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Jun
9
awarded  Autobiographer
May
28
comment Is $\gcd(a,bc)=\gcd(a,b)\gcd({a\over\gcd(a,b)}, c)$?
Thanks Marc, great explanation :)
May
27
awarded  Scholar
May
27
accepted Is $\gcd(a,bc)=\gcd(a,b)\gcd({a\over\gcd(a,b)}, c)$?
May
27
awarded  Student
May
27
awarded  Editor
May
27
revised Is $\gcd(a,bc)=\gcd(a,b)\gcd({a\over\gcd(a,b)}, c)$?
Added attempt at proof
May
27
asked Is $\gcd(a,bc)=\gcd(a,b)\gcd({a\over\gcd(a,b)}, c)$?
May
27
awarded  Informed
Jan
3
awarded  Supporter