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visits member for 2 years, 3 months
seen Dec 1 at 22:44

May
14
awarded  Caucus
Apr
26
comment Can I use my powers for good?
@DanB I think that game development is important to society, since it has the potential to spill out benefits into other fields. See math.ucla.edu/~jteran
Apr
23
revised Stability of a matrix
briefed it
Apr
23
suggested approved edit on Stability of a matrix
Apr
1
comment What's the relationship between singular, nontrivial and linear dependent? Basic linear algebra question.
Here's an explanation of points 1-4 of the Invertible Matrix Theorem provided in the answer: 1. $A^{-1}$ exists. 2. $A$ can be obtained from the identity matrix, $I$ by a finite number of row operations. 3. All columns and rows of $A$ are linearly independent. 4. "For a linear map $f:A \to B$, the kernel of $f$ is the set of elements of $A$ that map to $0$ in $B$. The kernel is trivial if it contains only the single element $0$ (which must map to $0$ in $B$ by linearity)." - Henning Makholm chat.stackexchange.com/transcript/message/8765408#8765408
Apr
1
suggested rejected edit on What's the relationship between singular, nontrivial and linear dependent? Basic linear algebra question.
Apr
1
revised What's the relationship between singular, nontrivial and linear dependent? Basic linear algebra question.
added 616 characters in body
Apr
1
comment What's the relationship between singular, nontrivial and linear dependent? Basic linear algebra question.
What's a trivial kernel?
Mar
18
revised $\lim_{n \to \infty} \frac{\ln x^q}{x^p}$ not necessarily =0 for any $p>0$ and $q>0$ right?
changed n to x
Mar
18
accepted $\lim_{n \to \infty} \frac{\ln x^q}{x^p}$ not necessarily =0 for any $p>0$ and $q>0$ right?
Mar
18
asked $\lim_{n \to \infty} \frac{\ln x^q}{x^p}$ not necessarily =0 for any $p>0$ and $q>0$ right?
Mar
18
awarded  Quorum
Mar
17
revised Can $|-x^2| < 1 $ imply that $-1<x<1$?
spelling mistaked ? I difxed it@OIH!
Mar
17
suggested approved edit on Can $|-x^2| < 1 $ imply that $-1<x<1$?
Mar
17
accepted Can $|-x^2| < 1 $ imply that $-1<x<1$?
Mar
17
comment Can $|-x^2| < 1 $ imply that $-1<x<1$?
Lol, I get it. I just missed the step $|-x^2|=|x^2|$
Mar
17
revised Can $|-x^2| < 1 $ imply that $-1<x<1$?
deleted 22 characters in body; edited title
Mar
17
revised Can $|-x^2| < 1 $ imply that $-1<x<1$?
deleted 22 characters in body; edited title
Mar
17
asked Can $|-x^2| < 1 $ imply that $-1<x<1$?
Mar
10
awarded  Civic Duty