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| bio | website | |
|---|---|---|
| location | Los Angeles, CA | |
| age | 17 | |
| visits | member for | 8 months |
| seen | 3 hours ago | |
| stats | profile views | 77 |
Undergraduate Physics major at UCLA.
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Dec 27 |
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Approximating vertical probability distribution of double pendulum I would use the solutions to the usual 2D double pendulum to calculate the path for arbitrary m,M,l and L, and then 'compress' the path into a circular probability distribution (the circumference) and then make an equation describing the vertical probability |
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Dec 27 |
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Approximating vertical probability distribution of double pendulum A 2D double pendulum. The distance between each pair of pendulums is constant. |
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Dec 27 |
revised |
Approximating vertical probability distribution of double pendulum added initial step |
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Dec 27 |
asked | Approximating vertical probability distribution of double pendulum |
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Dec 24 |
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Mind-blowing mathematics experiments @Adam here's the original (480p!) video youtube.com/watch?feature=player_embedded&v=wO61D9x6lNY |
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Nov 18 |
accepted | What's the relationship between singular, nontrivial and linear dependent? Basic linear algebra question. |
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Nov 4 |
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Show that $g'(0)\neq \lim_{x\to 0} g'(x)$ Thanks! When finding the limit, we use the equation of $g(x)$ for $x\neq0$ but when using limit definition, we use $g(0)=0$ while computing $g'(0)$. |
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Nov 4 |
awarded | Commentator |
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Nov 4 |
revised |
Show that $g'(0)\neq \lim_{x\to 0} g'(x)$ added 107 characters in body |
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Nov 4 |
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Show that $g'(0)\neq \lim_{x\to 0} g'(x)$ There's a chance that the question is incorrect because the textbook has a typo |
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Nov 4 |
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Show that $g'(0)\neq \lim_{x\to 0} g'(x)$ The limit $\lim_{x\to0}g'(x)=2\lim_{x\to0}x \sin\frac1x-\lim_{x\to0}\cos\frac1x$ doesn't exist but the limit $g'(0)=\lim_{h\to 0}\frac{g(0+h)-g(0)}h=\lim_{h\to0}\frac{g(h)}h=\lim_{h\to 0}\frac{h^2\sin\frac1h}h=\lim_{h\to 0}h\sin\frac1h\;;\tag{1}$ exists |
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Nov 4 |
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Show that $g'(0)\neq \lim_{x\to 0} g'(x)$ It seems to me that $g'(0)=\lim_{x\to 0} g'(x)$ so I can't prove $g'(0)\neq \lim_{x\to 0} g'(x)$ |
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Nov 4 |
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Show that $g'(0)\neq \lim_{x\to 0} g'(x)$ yeah it's 0.wolframalpha.com/input/?i=limit+h+sin+1%2Fh |
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Nov 4 |
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Show that $g'(0)\neq \lim_{x\to 0} g'(x)$ If $lim_{x\to0}g'(x)=0$ and $g'(0)=0$, how could $g'(0)\neq \lim_{x\to 0} g'(x)$? |
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Nov 4 |
revised |
Show that $g'(0)\neq \lim_{x\to 0} g'(x)$ added 4 characters in body |
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Nov 4 |
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Show that $g'(0)\neq \lim_{x\to 0} g'(x)$ Using Brian's equation, I find $lim_{x\to0}g'(x)=0$ |
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Nov 4 |
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Show that $g'(0)\neq \lim_{x\to 0} g'(x)$ Information on $lim_{x\to0}g'(x)$ wolframalpha.com/input/?i=limit+2xsin(1%2fx)-cos(1%2fx) |
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Nov 4 |
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Show that $g'(0)\neq \lim_{x\to 0} g'(x)$ I think a mistake I made is I didn't use the limit definition yet, rather I directly computed g'(x) at $x\neq0$. |
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Nov 4 |
asked | Show that $g'(0)\neq \lim_{x\to 0} g'(x)$ |
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Nov 4 |
answered | Determining diameter of parachute to obtain specific landing speed of a body, with Differential Equations |
