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Feb
21
revised How to show Boolean identity : $(ab + c + d)(c' + d)(c' + d + e) = abc' + d$
rolled back to a previous revision
Feb
21
revised How to show Boolean identity : $(ab + c + d)(c' + d)(c' + d + e) = abc' + d$
rolled back to a previous revision
Feb
21
revised Need help converting a number into IEEE floating point format
rolled back to a previous revision
Feb
21
revised How to show Boolean identity : $(ab + c + d)(c' + d)(c' + d + e) = abc' + d$
rolled back to a previous revision
Feb
21
revised How to show Boolean identity : $(ab + c + d)(c' + d)(c' + d + e) = abc' + d$
rolled back to a previous revision
Feb
21
revised Need help converting a number into IEEE floating point format
rolled back to a previous revision
Feb
21
revised How to show Boolean identity : $(ab + c + d)(c' + d)(c' + d + e) = abc' + d$
rolled back to a previous revision
Feb
21
revised Need help converting a number into IEEE floating point format
rolled back to a previous revision
Feb
21
revised Need help converting a number into IEEE floating point format
rolled back to a previous revision
Feb
21
awarded  Cleanup
Feb
21
revised How to show the polynomial $P= x^{10}+ax^9+bx^8+cx^7+x+1$ always has at least one non-real root?
made title more descriptive
Feb
21
revised How to show Boolean identity : $(ab + c + d)(c' + d)(c' + d + e) = abc' + d$
rolled back to a previous revision
Feb
21
revised How to show Boolean identity : $(ab + c + d)(c' + d)(c' + d + e) = abc' + d$
restored original question, couldn't roll back
Feb
21
awarded  Custodian
Feb
21
reviewed Approve suggested edit on The number of real roots of $(x+3)^4 + (x+5)^4 = 16$
Feb
21
comment Why $\int_{-1}^1 \frac{1}{x^3}\, \mathrm{d} x \neq 0$?
related: math.stackexchange.com/questions/180239/…
Feb
21
revised Why $\int_{-1}^1 \frac{1}{x^3}\, \mathrm{d} x \neq 0$?
made title more descriptive
Feb
21
suggested suggested edit on How to show the polynomial $P= x^{10}+ax^9+bx^8+cx^7+x+1$ always has at least one non-real root?
Feb
21
revised How can I simplify $\frac{\sqrt{x} + 1}{x\sqrt{x} + x + \sqrt{x}} : \frac{1}{x^2-\sqrt{x}}$?
made title more descriptive
Feb
21
suggested suggested edit on How can I simplify $\frac{\sqrt{x} + 1}{x\sqrt{x} + x + \sqrt{x}} : \frac{1}{x^2-\sqrt{x}}$?