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Nov
4
reviewed Close regular graph (dividing vertices togroups of edges and circles)
Nov
4
reviewed Close Substitution identities: $\mu(x/ \sigma)(y/\tau) = \mu(x/ \sigma, y/\tau) = \mu(y/\tau)(x/\sigma)$
Nov
4
answered Prove that $(|u-s|+|x-y|)^2\leq 2|u-s|^2+2|x-y|^2$.
Nov
4
answered What exactly is a stationary point?
Nov
4
answered Prove not mutually independent
Nov
4
revised Prove not mutually independent
added 16 characters in body
Nov
4
answered On the definition of an exact sequence in an abelian category
Nov
4
comment On the definition of an exact sequence in an abelian category
@AlexYoucis Yes, that is apparently what is meant.
Nov
4
comment On the definition of an exact sequence in an abelian category
@AlexYoucis I read "isomorphic as subobjects" (otherwise it would indeed be a trivial task to find counterexamples).
Nov
4
comment Are Base Ten Logarithms Relics?
@mjqxxxx Basing your units of powers of$10$ is different from working with $\log_{10}$. You don't calculate the area of a 3 nm by 4 km rectangle by computing $\log_{10}3+\log_{10}4$, you multiply mantissas and add/cancel exponents to obtain 12 mm² (I did this in my head and the result is exact - nothing one expects from a calculation involving logarithms)
Nov
4
comment Are Base Ten Logarithms Relics?
@AndréNicolas what "many formulas" except possibly those involving decibels? What comes to my mind (Boltzman stats, decay, dampening) seems to make use of $e$ typically
Nov
4
comment A and complement A
So there are exactly two special cases under which $A$ and $A'$ are independant
Nov
4
comment Google Question: Number of ways to select sets such that n is pure
@JonathanY. I guess $\operatorname{rank}(k)=|\{\,x\in S\mid x\le k\,\}|$.
Nov
4
answered Pythagoras numbers and fermats last theorem
Nov
4
comment The 'abelian group' custom
@DanielRust Then you seem to be very influential, especially in the field of decaying metals :)
Nov
4
comment The 'abelian group' custom
@StefanH In German there are in fact rules that abelsch is correct, otherwise one would write Abel'sch; also it should be either Noether'scher Ring or noetherscher Ring. I'm not sure if the English morphologoy has similar rules, e.g. for -ian vs. -otic.
Nov
4
comment Prove infinity arithmatics
Then you need to show that $a_n\to +\infty$, $b_n\to -\infty$ implies $a_nb_n\to-\infty$ etc. (Then again, you still need to remark that yo will accept this as proof because you want to employ the permanence principle accordingly)
Nov
4
answered If a sequnce $(a_n)_n \to L$, $(\sqrt{a_n})_n \to \sqrt L$
Nov
4
answered Total number of divisors is a prime
Nov
4
answered Prove the following language is not regular