Leonardo
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 Jan 26 asked How would one prove that $\sqrt{n}$ is the largest divisor that needs to be checked to determine if $n$ is prime? Jan 25 accepted If I am checking for $s$ divides $n$ on the interval $S = [3, n-x]$, how large can I make $x$ to ensure I have verified $n$ is prime? Jan 25 comment If I am checking for $s$ divides $n$ on the interval $S = [3, n-x]$, how large can I make $x$ to ensure I have verified $n$ is prime? Actually, I have a feeling my first statement is false, let x = 3. Jan 25 asked If I am checking for $s$ divides $n$ on the interval $S = [3, n-x]$, how large can I make $x$ to ensure I have verified $n$ is prime? Jan 22 revised How would one prove this in predicate logic markup changes Jan 22 suggested approved edit on How would one prove this in predicate logic Jan 22 accepted Have I justified that $\forall x \in \mathbb{R}$, $x > 1 \rightarrow x^2 > x$ Jan 22 awarded Custodian Jan 22 reviewed Reject Have I justified that $\forall x \in \mathbb{R}$, $x > 1 \rightarrow x^2 > x$ Jan 22 comment Have I justified that $\forall x \in \mathbb{R}$, $x > 1 \rightarrow x^2 > x$ That square I put there was a test to see how this community would accept it. My instructor claims that it is common to denote the end of a proof with this strange looking notation. Jan 22 comment Have I justified that $\forall x \in \mathbb{R}$, $x > 1 \rightarrow x^2 > x$ @HSN I am not taking abstract linear algebra. So your first hypothesis is true. This course is an introduction to elementary discrete mathematics. Jan 22 asked Have I justified that $\forall x \in \mathbb{R}$, $x > 1 \rightarrow x^2 > x$ Jan 15 accepted Is the set $\{1\}$ a member, and not a subset of the power set of $\{1, 2\}$? Jan 15 comment Is the set $\{1\}$ a member, and not a subset of the power set of $\{1, 2\}$? Thank you for confirming, some of the question get a bit sticky. Jan 15 asked Is the set $\{1\}$ a member, and not a subset of the power set of $\{1, 2\}$? Jan 15 comment Is my answer correct to this homework involving sets? I am glad you caught that so quick, it seemed apparent that I was missing something to this but I could not define what it was. Jan 15 accepted Is my answer correct to this homework involving sets? Jan 15 comment Is my answer correct to this homework involving sets? Yes I see your point, I was doing things a bit too implicitly and that is why I was unsure of my own reasoning. Thanks! Jan 15 revised Is my answer correct to this homework involving sets? fixed equation to intersection not union Jan 15 comment Is my answer correct to this homework involving sets? So if 1 person is wearing blue and green, then $G = 1$, $B = 1$, $|G \cap B| = 1$