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Jan
25
comment If I am checking for $s$ divides $n$ on the interval $S = [3, n-x]$, how large can I make $x$ to ensure I have verified $n$ is prime?
Actually, I have a feeling my first statement is false, let x = 3.
Jan
25
asked If I am checking for $s$ divides $n$ on the interval $S = [3, n-x]$, how large can I make $x$ to ensure I have verified $n$ is prime?
Jan
22
revised How would one prove this in predicate logic
markup changes
Jan
22
suggested approved edit on How would one prove this in predicate logic
Jan
22
accepted Have I justified that $\forall x \in \mathbb{R}$, $x > 1 \rightarrow x^2 > x$
Jan
22
awarded  Custodian
Jan
22
reviewed Reject Have I justified that $\forall x \in \mathbb{R}$, $x > 1 \rightarrow x^2 > x$
Jan
22
comment Have I justified that $\forall x \in \mathbb{R}$, $x > 1 \rightarrow x^2 > x$
That square I put there was a test to see how this community would accept it. My instructor claims that it is common to denote the end of a proof with this strange looking notation.
Jan
22
comment Have I justified that $\forall x \in \mathbb{R}$, $x > 1 \rightarrow x^2 > x$
@HSN I am not taking abstract linear algebra. So your first hypothesis is true. This course is an introduction to elementary discrete mathematics.
Jan
22
asked Have I justified that $\forall x \in \mathbb{R}$, $x > 1 \rightarrow x^2 > x$
Jan
15
accepted Is the set $\{1\}$ a member, and not a subset of the power set of $\{1, 2\}$?
Jan
15
comment Is the set $\{1\}$ a member, and not a subset of the power set of $\{1, 2\}$?
Thank you for confirming, some of the question get a bit sticky.
Jan
15
asked Is the set $\{1\}$ a member, and not a subset of the power set of $\{1, 2\}$?
Jan
15
comment Is my answer correct to this homework involving sets?
I am glad you caught that so quick, it seemed apparent that I was missing something to this but I could not define what it was.
Jan
15
accepted Is my answer correct to this homework involving sets?
Jan
15
comment Is my answer correct to this homework involving sets?
Yes I see your point, I was doing things a bit too implicitly and that is why I was unsure of my own reasoning. Thanks!
Jan
15
revised Is my answer correct to this homework involving sets?
fixed equation to intersection not union
Jan
15
comment Is my answer correct to this homework involving sets?
So if 1 person is wearing blue and green, then $G = 1$, $B = 1$, $|G \cap B| = 1$
Jan
15
comment Can you show why zero divided by zero does not equal zero?
@GilYoungCheong Unfortunately $0^{-1}$ is equally as undefined as $1/0$ which makes sense because you are correct they should be the same in any other example that do not include zero.
Jan
15
asked Is my answer correct to this homework involving sets?