Leonardo
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 Jan25 asked If I am checking for $s$ divides $n$ on the interval $S = [3, n-x]$, how large can I make $x$ to ensure I have verified $n$ is prime? Jan22 revised How would one prove this in predicate logic markup changes Jan22 suggested approved edit on How would one prove this in predicate logic Jan22 accepted Have I justified that $\forall x \in \mathbb{R}$, $x > 1 \rightarrow x^2 > x$ Jan22 awarded Custodian Jan22 reviewed Reject Have I justified that $\forall x \in \mathbb{R}$, $x > 1 \rightarrow x^2 > x$ Jan22 comment Have I justified that $\forall x \in \mathbb{R}$, $x > 1 \rightarrow x^2 > x$ That square I put there was a test to see how this community would accept it. My instructor claims that it is common to denote the end of a proof with this strange looking notation. Jan22 comment Have I justified that $\forall x \in \mathbb{R}$, $x > 1 \rightarrow x^2 > x$ @HSN I am not taking abstract linear algebra. So your first hypothesis is true. This course is an introduction to elementary discrete mathematics. Jan22 asked Have I justified that $\forall x \in \mathbb{R}$, $x > 1 \rightarrow x^2 > x$ Jan15 accepted Is the set $\{1\}$ a member, and not a subset of the power set of $\{1, 2\}$? Jan15 comment Is the set $\{1\}$ a member, and not a subset of the power set of $\{1, 2\}$? Thank you for confirming, some of the question get a bit sticky. Jan15 asked Is the set $\{1\}$ a member, and not a subset of the power set of $\{1, 2\}$? Jan15 comment Is my answer correct to this homework involving sets? I am glad you caught that so quick, it seemed apparent that I was missing something to this but I could not define what it was. Jan15 accepted Is my answer correct to this homework involving sets? Jan15 comment Is my answer correct to this homework involving sets? Yes I see your point, I was doing things a bit too implicitly and that is why I was unsure of my own reasoning. Thanks! Jan15 revised Is my answer correct to this homework involving sets? fixed equation to intersection not union Jan15 comment Is my answer correct to this homework involving sets? So if 1 person is wearing blue and green, then $G = 1$, $B = 1$, $|G \cap B| = 1$ Jan15 comment Can you show why zero divided by zero does not equal zero? @GilYoungCheong Unfortunately $0^{-1}$ is equally as undefined as $1/0$ which makes sense because you are correct they should be the same in any other example that do not include zero. Jan15 asked Is my answer correct to this homework involving sets? Jan15 comment Can you show why zero divided by zero does not equal zero? @GilYoungCheong Does this not also work for real numbers too?