Alex
Reputation
11,562
Top tag
Next privilege 15,000 Rep.
Protect questions
 Jan 21 comment $96$ balls in $4$ boxes I think this does not take into account the capacity of the box Jan 20 comment How to solve this limit $\lim _{x\to 1}\left(\frac{\ln \left(\left|x-2\right|\right)}{\ln \left(x\right)}\right)$? What about Taylor series? Jan 20 revised Why do I get one extra wrong solution? edited tags Jan 19 answered Why do I get one extra wrong solution? Jan 19 comment Why do I get one extra wrong solution? In fact $x=2$ is also a wrong solution...it should be $x=4$ Jan 18 comment Round table seating probability question please use latex Jan 18 revised Round table seating probability question edited tags Jan 18 comment To find Radius of convergence of series $1 + \frac{1.x^2}{2.3} + \frac{1.3.x^4}{2.4.5} + \frac{1.3.5.x^6}{2.4.6.7}$ @SophieClad: Sorry, but it is not how it works on MSE. You must show all your attempts. Jan 17 comment How to identify what probability distribution this is? Yeah, what makes you think this is a pdf at all? Did you obtain it emprically? Jan 14 comment Poisson distribution probabilities are not linear?? You can have 3 occasions in the second half for example Jan 14 comment Poisson distribution probabilities are not linear?? 4 per hour doesn't mean 2 per half-hour Jan 14 comment Is $\lim_{n\to\infty}\frac{n(a_n-a_{n+1})}{a_{n+1}}=0$ if $\sum_{n\geq 1} a_n/n$ diverges? @sirfoga: plug in $\frac{1}{n}$ into the limit you have: it does not converge to 0 Jan 14 comment Is $\lim_{n\to\infty}\frac{n(a_n-a_{n+1})}{a_{n+1}}=0$ if $\sum_{n\geq 1} a_n/n$ diverges? simply use $a_n = \frac{1}{n}$ to see that the statement is wrong Jan 13 comment Improper definite integral $\int_0^\infty e^{-x^2}(x + k)^\alpha dx$ wh do you think it exists in closed form at all? Jan 13 revised finding the probability of not being answered more than two calls! added 9 characters in body Jan 12 comment Conditional probability - Proof did you try law of total probability? Jan 11 revised How to prove $\sum_{i=1}^ki^k(-1)^{k-i}\binom {k+1}{i} =(k+1)^k$ edited tags Jan 10 answered Permutations- the number of six digit integers that are even Jan 10 comment How far can you go with the fact that “powers beat logs”? yes good point thanks Jan 10 revised How far can you go with the fact that “powers beat logs”? deleted 3 characters in body