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seen Mar 12 at 10:45

Jan
22
comment Build the function by its values. Only combination of +, -, *, abs() allowed for this function.
Sorry, my fault. In this case I get: f(x[k])=y[0]+sum_from_1_to_n(y[k]-y[k-1]). Right? That's y[n], not y[k].
Jan
22
comment Build the function by its values. Only combination of +, -, *, abs() allowed for this function.
I'm sorry I doubt f(x[k]) is equal to y[k]. It is f(x[k])=y[0]+0.5*sum_from_1_to_n(y[k]-y[k-1])=0.5*y[0]+0.5*y[n] <>y[k].
Jan
22
comment Build the function by its values. Only combination of +, -, *, abs() allowed for this function.
Yes, they are allowed. Thank you.
Jan
21
revised Build the function by its values. Only combination of +, -, *, abs() allowed for this function.
added 4 characters in body
Jan
21
comment Build the function by its values. Only combination of +, -, *, abs() allowed for this function.
I edited the question already. I'm sorry for your time. Thank you. Just made it bold.
Jan
21
revised Build the function by its values. Only combination of +, -, *, abs() allowed for this function.
added 74 characters in body
Jan
21
comment Build the function by its values. Only combination of +, -, *, abs() allowed for this function.
Sorry, I don't want to use a polynomial, that's why I asked this question. Only the combination of abs of the first degree. Sorry I wasn't clear.
Jan
21
asked Build the function by its values. Only combination of +, -, *, abs() allowed for this function.
Jan
20
comment the simplest function f(1)=-1; f(2)=0; f(3)=1; f(4)=0.
Thank you for your answer, but −|x−3|+1 looks much simpler in my case.
Jan
20
comment the simplest function f(1)=-1; f(2)=0; f(3)=1; f(4)=0.
Thank you for −|x−3|+1. That's exactly what I need - the easiest among the other answers. So, you were able to use the function of a*|x-b|+c. How were you sure there is such a function? Just curios, no answer is requested. I accept your answer as the best one for my purposes. Thank you.
Jan
20
accepted the simplest function f(1)=-1; f(2)=0; f(3)=1; f(4)=0.
Jan
20
asked the simplest function f(1)=-1; f(2)=0; f(3)=1; f(4)=0.
Dec
13
awarded  Critic
Dec
13
revised Looking for monotonic function example that satisfies several conditions
added 2 characters in body
Dec
13
asked Looking for monotonic function example that satisfies several conditions
Nov
26
accepted Simple probability question I can't solve: not enough data?
Dec
20
awarded  Editor
Dec
20
revised Simple probability question I can't solve: not enough data?
added 180 characters in body
Dec
20
asked Simple probability question I can't solve: not enough data?
Aug
24
awarded  Scholar