345 reputation
115
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location United States
age 33
visits member for 2 years, 3 months
seen Nov 25 at 22:08

I'm earning my PhD in mathematics and have been employed as an analyst since graduating college in 2003.


Apr
22
revised Algebra problem stumping me
added 22 characters in body
Apr
22
comment Algebra problem stumping me
$y$ is $7$, not $5$. But you did beat me to the other letters by a bit.
Apr
22
answered Algebra problem stumping me
Apr
22
comment Algebra problem stumping me
@DanielV See 2 comments up, 2 minutes before your comment. "Let me check $total=RHS$." :)
Apr
22
comment Algebra problem stumping me
@user144808 I meant missing from my formula, not your question. ;-)
Apr
22
comment Algebra problem stumping me
Yep, None of those 31 satisfy uniqueness. (For $total=45$. Let me check $total=RHS$.)
Apr
22
comment Algebra problem stumping me
@DanielV The output is basically just a text string (display wise). There may be functions that would do that, but I'm still new to Mathematica. The fastest way for me to try that would be to dump it into Excel. (But the long time makes me think none of those 31 satisfy the uniqueness condition.)
Apr
22
comment Algebra problem stumping me
@user144808 Hmm, with the 36 inequalities enforcing uniqueness it's taking too long to run, to expect a good solution. (For either interpretation of $total$.)
Apr
22
comment Algebra problem stumping me
@Keith The sum of the RHS view gives 45 possibilities (before enforcing uniqueness). Give me a bit to encode the uniqueness.
Apr
22
comment Algebra problem stumping me
Ah, yes! A missing assumption.
Apr
22
revised Algebra problem stumping me
Better tags
Apr
22
suggested suggested edit on Algebra problem stumping me
Apr
22
revised Algebra problem stumping me
added 132 characters in body
Apr
22
answered Algebra problem stumping me
Apr
22
comment Algebra problem stumping me
@MattAllegro No, $E\in \{1,2\}$. I'll paste what I've got as an answer.
Apr
22
comment Algebra problem stumping me
In all 31 cases, $C=1$. $E$ is either a $1$ or $2$ (with approximately equal likelihood).
Apr
22
comment Algebra problem stumping me
In only 1 of those 31 cases, is the first $?$ a $2$. In the other 30 cases, it's a $1$.
Apr
22
comment Algebra problem stumping me
@user144808 Is there anything in the problem that's missing above? Where did $A-H>F$ come from? It seems odd for that not to be included in the list of equations.
Apr
22
comment Algebra problem stumping me
Hmm, I programmed everything I can see about the problem into Mathematica, and it reduced it to 31 different possible cases. (That was assuming $total=1+2+\dots+9=45$ which implies $B=4$ and the second $?=5$.)
Apr
22
comment Algebra problem stumping me
@user112061 If you use $X$ in the first $?$, I'd use $Y$ as the second $?$. Maybe $X=Y$. Maybe not. But setting both $?$ to $X$ only considers the first possibility.