network profile
| bio | website | kenbellows.com |
|---|---|---|
| location | Baltimore, MD | |
| age | 22 | |
| visits | member for | 9 months |
| seen | May 15 at 16:51 | |
| stats | profile views | 2 |
I'm a software developer in the Baltimore/DC Metro area. I'm an alumni of Rensselaer Polytechnic Institute. I graduated in 2012 with a BS in Computer Science.
I'm also an avid Christian, guitarist, and music junkie.
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Jan 25 |
awarded | Autobiographer |
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Aug 20 |
awarded | Supporter |
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Aug 20 |
comment |
Why is the last digit of $n^5$ equal to the last digit of $n$? What I love about this is that not only will $n^1,5,9,...$ end in $n$, but if you observe the in between powers, there is always a four number cycle. e.g. for $3^k, k->\infty$, we observe the numbers $3, 9, 27, 81, 243, 729, 2187, 6561, 19683, ...$, rendering the cycle $3, 9, 7, 1$. |
