481 reputation
211
bio website
location
age
visits member for 2 years, 1 month
seen 9 hours ago

Sep
9
answered connection on a vector bundle. horizontal spaces canonically isomorphic to horizontal spaces in the projection
Sep
7
revised connection on a vector bundle. horizontal spaces canonically isomorphic to horizontal spaces in the projection
added 16 characters in body
Sep
7
revised connection on a vector bundle. horizontal spaces canonically isomorphic to horizontal spaces in the projection
added 119 characters in body
Sep
7
asked connection on a vector bundle. horizontal spaces canonically isomorphic to horizontal spaces in the projection
Aug
31
accepted Don't understand Levi decomposition theorem
Aug
28
asked Don't understand Levi decomposition theorem
Aug
15
awarded  Yearling
Aug
12
comment Symmetry group of the vector field $V=x \partial /\partial x + y \partial /\partial y$
I don't see from here why this implies $g$ is linear
Aug
12
comment Symmetry group of the vector field $V=x \partial /\partial x + y \partial /\partial y$
I added the "To be more specific..."
Aug
12
revised Symmetry group of the vector field $V=x \partial /\partial x + y \partial /\partial y$
added 283 characters in body
Aug
7
comment Symmetry group of the vector field $V=x \partial /\partial x + y \partial /\partial y$
No, in your case the integral curves would be $(xe^t,ye^t)$, in my previous comment it should be $t$ instead of $x$ its a typo sorry
Aug
7
comment Symmetry group of the vector field $V=x \partial /\partial x + y \partial /\partial y$
the integral curves are just $x=Ae^x$, $y=Be^x$, so lines out of the origin plus the origin. @JonHerman, I don't see how this can help
Aug
7
answered Symmetry group of the vector field $V=x \partial /\partial x + y \partial /\partial y$
Aug
7
asked Symmetry group of the vector field $V=x \partial /\partial x + y \partial /\partial y$
Jul
19
comment Is a 1-form locally expressible as $dx$?
Sorry I don't understand your last comment. What I meant is that in that coordinate neighbourhood $(x_1,...,x_n)$, the dual of $\alpha$ is a vector field that can be represented as $\partial/\partial x_1$ (the rest of the vector fields that I constructed I agree won't be necessarily of the form $\partial/\partial x_i$ but I don't need that for my argument.
Jul
18
comment Is a 1-form locally expressible as $dx$?
True, but I can always find and integral curve of one of them, in this case of the one corresponding to the dual of $\alpha$. So every point will have a coordinate neighborhood in which the first coordinate gives the dual of $\alpha$. I´m not saying the same thing holds for all the others at once.
Jul
18
asked Is a 1-form locally expressible as $dx$?
Jul
17
answered Orthonormal Projection Proof
Jul
2
awarded  Curious
Feb
9
accepted Extending an independent set of vectors to a basis