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Jan
1
comment Function and sequence
How do you get $u_0 > u_1$ in question 5?
Jan
1
comment Conversion of the Gauss law $\nabla \cdot E = \frac{\rho } {\epsilon_0}$ into integral form
Basically, you're going back from Maxwell's first equation $\nabla \cdot E = \frac{\rho}{\epsilon_0}$ to Gauss' law $\Phi_E = \frac{Q}{\epsilon_0}$. As Siminore has pointed out, your notation is a bit problematic.
Jan
1
reviewed Approve Eigenvectors of $2\times 2$ real symmetric matrix
Jan
1
comment Cauchy product of two different series
What did you try?
Jan
1
revised What is $\rightarrowtail$ used for?
edited tags
Jan
1
revised Diagonalization versus s.d. product for non-commuting Hermitian matrices
deleted 9 characters in body
Jan
1
comment What is $\rightarrowtail$ used for?
Knowing a map is an injection is often better than only knowing it is a map. See: en.wikipedia.org/wiki/Injective_function
Jan
1
answered What is $\rightarrowtail$ used for?
Jan
1
answered Diagonalization versus s.d. product for non-commuting Hermitian matrices
Jan
1
revised Forming contrapositive
edited tags
Jan
1
revised Forming contrapositive
added 319 characters in body
Jan
1
answered Forming contrapositive
Dec
31
reviewed Approve Is the complement of an open ball in a Banach space connected?
Dec
31
answered Non-zero eigenvalues of $AA^T$ and $A^TA$
Dec
31
answered help on a specific power series expansion, i cannot see what the author did here
Dec
31
comment Integral of an exponential
Where do you get stuck when using the hint?
Dec
31
accepted $U \subset \mathbb{C}$ open, how do I construct $f$ holomorphic, such that there is no continuation of $f$ on any neighbourhood of $z \in \partial U$?
Dec
31
answered $U \subset \mathbb{C}$ open, how do I construct $f$ holomorphic, such that there is no continuation of $f$ on any neighbourhood of $z \in \partial U$?
Dec
31
accepted How should I think about reflexive spaces? What “property” do I get from a space being reflexive?
Dec
31
comment inequality for point on a sphere
@Dr.SonnhardGraubner: Why would that cause trouble? This would only imply that $\sqrt{1-a} < \sqrt{a}$, which is perfectly fine.