2,120 reputation
21446
bio website anhhuy.ch
location Switzerland
age 22
visits member for 4 years, 1 month
seen 2 mins ago

My name is Anh Huy Truong and I am currently studying mathematics at the ETH Zürich.


Nov
30
accepted Understanding the intermediate field method for the $\phi^4$ interaction
Nov
29
awarded  Popular Question
Nov
22
awarded  Promoter
Nov
22
comment Planning a mockup maths class for high school related to river reactivation
(or just of river regulation, sorry, I missed the 5 minute edit time span)
Nov
22
comment Planning a mockup maths class for high school related to river reactivation
@WillieWong: It is the inversion of canalisation of a river.
Nov
22
awarded  Informed
Nov
22
revised Understanding the intermediate field method for the $\phi^4$ interaction
I resolved the first question but have different questions now, still very related to the second question, which is why I'm changing the post.
Nov
21
awarded  Yearling
Nov
21
accepted How to show $\mu(\overline{\mathbb{R}}) = \overline{\mathbb{R}}$ iff $a, b, c, d \in \mathbb{R}$ for $\mu(z) = \frac{az+b}{cz+d}$?
Nov
20
asked Understanding the intermediate field method for the $\phi^4$ interaction
Nov
20
accepted Concerning the distribution of a random variable of a random walk that doesn't make any sense to me
Aug
21
accepted Proving Sylow's first theorem
Aug
21
comment Proving Sylow's first theorem
Which implication are you talking about?
Aug
21
comment Proving Sylow's first theorem
Yes, $S_i$ is not necessarily a subgroup. That is the point of the equation $\operatorname{Stab}_G(S_i) = S_i$: As the stabilizer IS a subgroup, it implies that $S_i$ is too.
Aug
21
comment Proving Sylow's first theorem
Aren't order and cardinality of sets the same thing?
Aug
21
comment Proving Sylow's first theorem
Yes, I meant that $p$ cannot divide the cardinality of the orbit $S_i$ (I never said order, did I?). Also, I fixed a mistake. The way I understand the proof is that we have an orbit such that $p$ doesn't divide its cardinality and then find $\operatorname{Stab}_G(S_i) = S_i$ (but I don't know why this equation holds). This equation implies that the stabilizer and $S_i$ have the same cardinality and as the stabilizer is a subgroup (of cardinality $p^n$), we are done.
Aug
21
revised Proving Sylow's first theorem
added 1 characters in body
Aug
21
comment Proving Sylow's first theorem
$S_i$ only represents the orbit $GS_i$.
Aug
21
revised Proving Sylow's first theorem
added 15 characters in body
Aug
21
asked Proving Sylow's first theorem