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Jan
2
answered Does order of qualifiers matter in FOL formula?
Jan
2
revised Does order of qualifiers matter in FOL formula?
added 126 characters in body
Jan
2
reviewed Reviewed Find the cardinality of $\mathbb{F}_2$ adjoin a root of $X^4 + X + 1$
Jan
2
revised Find the cardinality of $\mathbb{F}_2$ adjoin a root of $X^4 + X + 1$
added 42 characters in body; edited tags
Jan
1
reviewed Approve Use AM-GM to prove upper bound.
Jan
1
comment Integrate $ \int {1\over x^2(x-1)^3} \, dx $
@user1904218: You don't actually (explicitly) need substitution, you can use the chain rule which gives $((x-1)^{-1})' = -(x-1)^{-2}$ immediately.
Jan
1
revised Integrate $ \int {1\over x^2(x-1)^3} \, dx $
added 204 characters in body
Jan
1
answered Integrate $ \int {1\over x^2(x-1)^3} \, dx $
Jan
1
awarded  Revival
Jan
1
revised Understanding a “matrix repræsentation”
edited body
Jan
1
answered Understanding a “matrix repræsentation”
Jan
1
reviewed Approve Properties of solutions of system of integral equation.
Jan
1
reviewed No Action Needed Does the number of elements of order $r$ equal $\sum_{|x| = r} |x^G|$?
Jan
1
revised A simple proof that $\bigl(1+\frac1n\bigr)^n\leq3-\frac1n$?
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Jan
1
revised A simple proof that $\bigl(1+\frac1n\bigr)^n\leq3-\frac1n$?
added 2 characters in body
Jan
1
comment A simple proof that $\bigl(1+\frac1n\bigr)^n\leq3-\frac1n$?
By multiplying both sides of the second last inequality with $n(n-1)$, we get $-3(n-1) - n + 1 \leq -(n-1)$ which is equivalent to $-3n + 3 - n + 1 \leq -n + 1$, and by adding $3n-3$ to both sides, I ended up with $-n+1 \leq 2n-2$, if you're wondering. It seems simpler to just add $n-1$ to both sides, to retrieve $n \geq 1$ immediately. I changed the answer accordingly.
Jan
1
comment A simple proof that $\bigl(1+\frac1n\bigr)^n\leq3-\frac1n$?
Also, your last line implies that $\frac{3}{n+1} \leq 0$, which is wrong.
Jan
1
comment A simple proof that $\bigl(1+\frac1n\bigr)^n\leq3-\frac1n$?
You have a mistake in your calculations. Note that $$- \frac{n+1}{n(n+1)} - \frac{1}{n(n+1)} = \frac{-n-1-1}{n(n+1)} = -\frac{n+2}{n(n+1)}.$$
Jan
1
answered A simple proof that $\bigl(1+\frac1n\bigr)^n\leq3-\frac1n$?
Jan
1
revised Diagonalization versus s.d. product for non-commuting Hermitian matrices
added 112 characters in body; edited tags