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Dec
6
asked $U \subset \mathbb{C}$ open, how do I construct $f$ holomorphic, such that there is no continuation of $f$ on any neighbourhood of $z \in \partial U$?
Dec
1
accepted Is there a vector space that cannot be an inner product space?
Nov
30
comment Is there a vector space that cannot be an inner product space?
I'm sorry, in all lectures I have attended so far, the inner product is positive by definition, which is why I did not specify it.
Nov
29
awarded  Custodian
Nov
29
reviewed Reject Is there a vector space that cannot be an inner product space?
Nov
29
comment Is there a vector space that cannot be an inner product space?
I'm not sure, but can one not just use the well-ordering theorem?
Nov
29
asked Is there a vector space that cannot be an inner product space?
Nov
21
awarded  Yearling
Nov
16
awarded  Disciplined
Nov
8
asked How can I find $n$ such that $\sum_{k=1}^n f(k) \leq c$ without computing many partial sums?
Nov
5
accepted How can I make estimates on large powers and logarithms such as $e^{10}$?
Nov
4
revised How can I make estimates on large powers and logarithms such as $e^{10}$?
added 17 characters in body
Nov
4
asked How can I make estimates on large powers and logarithms such as $e^{10}$?
Oct
10
awarded  Notable Question
Oct
7
awarded  Tumbleweed
Aug
12
comment For $A \in \mathbb{R}^{3 \times 3}$, find $P, Q \in \mathbb{R}^{3 \times 3}$ such that $A = P-Q$, where $P^2 = P$, $Q^2 = Q$ and $PQ = 0 = QP$
@GerryMyerson: Why exactly? Is there some step that needs those eigenvalues?
Aug
12
accepted For $A \in \mathbb{R}^{3 \times 3}$, find $P, Q \in \mathbb{R}^{3 \times 3}$ such that $A = P-Q$, where $P^2 = P$, $Q^2 = Q$ and $PQ = 0 = QP$
Aug
12
asked For $A \in \mathbb{R}^{3 \times 3}$, find $P, Q \in \mathbb{R}^{3 \times 3}$ such that $A = P-Q$, where $P^2 = P$, $Q^2 = Q$ and $PQ = 0 = QP$
Aug
12
accepted Questions regarding the quadratic form $q: \bigwedge^2 \mathbb{R}^4 \to \bigwedge^4 \mathbb{R}^4, x \mapsto x \wedge x$
Aug
11
asked Questions regarding the quadratic form $q: \bigwedge^2 \mathbb{R}^4 \to \bigwedge^4 \mathbb{R}^4, x \mapsto x \wedge x$