ThroatOfWinter57

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visits member for 1 year, 11 months
seen 12 hours ago

I'm a dilettante programmer with many other interests including but not limited to math, physics, Singularitarianism, AI, music, and gaming.


Mar
13
revised Help understanding this 'Fractal' I've just made?
added 3 characters in body
Mar
13
revised Help understanding this 'Fractal' I've just made?
deleted 2 characters in body
Mar
13
comment Help understanding this 'Fractal' I've just made?
I think the lack of total self similarity fails it too. Also, sorry for the poor organization and overall messiness of the code. I was fooling around.
Mar
13
comment Help understanding this 'Fractal' I've just made?
I was weary about doing that since we're not on stack overflow but okay.
Mar
13
revised Help understanding this 'Fractal' I've just made?
corrected spelling; added 1287 characters in body
Mar
13
asked Help understanding this 'Fractal' I've just made?
Nov
13
revised Help me out with this related rate problem dealing with a cone?
added 6 characters in body
Nov
13
comment Help me out with this related rate problem dealing with a cone?
Oops. I'll make the change. Also, another issue, the title says "cylinder" not cone. I don't think I can change the title though.
Nov
13
asked Help me out with this related rate problem dealing with a cone?
Oct
13
awarded  Student
Oct
12
awarded  Tumbleweed
Oct
4
comment Equivalence of growth rate found through derivation of growth equation and rate found through $A = Pe^{rt}$.
A population of 500 bacteria is introduced into a culture and grows in number according to the equation P(t)=500(1+(4t/50+t^2)), where t is measured in hours. Find the rate at which the population is growing when t=2.
Oct
4
comment Equivalence of growth rate found through derivation of growth equation and rate found through $A = Pe^{rt}$.
So in other words, I have failed? Was using the Malthusian Growth Model completely wrong? To me at least the logic was sound; the variables and substitutions fit quite nicely.
Oct
4
awarded  Custodian
Oct
4
revised Equivalence of growth rate found through derivation of growth equation and rate found through $A = Pe^{rt}$.
added 2 characters in body
Oct
4
reviewed Approve suggested edit on Equivalence of growth rate found through derivation of growth equation and rate found through $A = Pe^{rt}$.
Oct
3
awarded  Editor
Oct
3
revised Equivalence of growth rate found through derivation of growth equation and rate found through $A = Pe^{rt}$.
added 8 characters in body
Oct
3
asked Equivalence of growth rate found through derivation of growth equation and rate found through $A = Pe^{rt}$.