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seen Jan 9 '13 at 8:38

Jun
9
awarded  Notable Question
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awarded  Popular Question
Aug
12
comment Why is the complex number $z=a+bi$ equivalent to the matrix form $\left(\begin{smallmatrix}a &-b\\b&a\end{smallmatrix}\right)$
Actually I ask this question because I want to know how to get the real-number matrix form of quaternions, thanks.
Aug
10
comment A funny question, about the source of complex number.
@J.M. it rotate $(-90^{\circ})$ ,you mean it is just a define?
Aug
10
asked A funny question, about the source of complex number.
Aug
10
awarded  Nice Question
Aug
10
awarded  Scholar
Aug
10
accepted Why is the complex number $z=a+bi$ equivalent to the matrix form $\left(\begin{smallmatrix}a &-b\\b&a\end{smallmatrix}\right)$
Aug
10
comment Why is the complex number $z=a+bi$ equivalent to the matrix form $\left(\begin{smallmatrix}a &-b\\b&a\end{smallmatrix}\right)$
Yes ,the question is the basic of the real-number matrix form of quaternions which is I really want to know next step.
Aug
10
comment Why is the complex number $z=a+bi$ equivalent to the matrix form $\left(\begin{smallmatrix}a &-b\\b&a\end{smallmatrix}\right)$
Very clear and easy understandable,thank you
Aug
10
awarded  Supporter
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9
awarded  Student
Aug
9
asked Why is the complex number $z=a+bi$ equivalent to the matrix form $\left(\begin{smallmatrix}a &-b\\b&a\end{smallmatrix}\right)$