Zack

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 Nov1 asked $a^4+b^2+c^2=2014$ Oct11 answered Graph single equation on calculator Sep24 awarded Autobiographer Sep17 awarded Tumbleweed Sep15 accepted $\displaystyle \frac{d}{dx}2^x$ where $x=0$ Sep15 comment $\displaystyle \frac{d}{dx}2^x$ where $x=0$ @Shahar Yes {need more characters} Sep15 comment $\displaystyle \frac{d}{dx}2^x$ where $x=0$ @user164587 Haha, I hadn't ever noticed that. I'm in Calc 1 and we still use log as base 10 if not specified. And most, if not all calculators, naturally use base 10 Sep15 revised $\displaystyle \frac{d}{dx}2^x$ where $x=0$ deleted 3 characters in body Sep15 asked $\displaystyle \frac{d}{dx}2^x$ where $x=0$ Sep14 comment Prove rigorously: $\displaystyle \lim_{x\rightarrow 2}x^2+5x=14$ So it's like squaring both sides? (But multiplying by equivalents) Sep13 comment Prove rigorously: $\displaystyle \lim_{x\rightarrow 2}x^2+5x=14$ How did you find $|x-2||x+7|<(9+ \delta)\delta$? Sep12 comment Prove rigorously: $\displaystyle \lim_{x\rightarrow 2}x^2+5x=14$ $\delta>|x-2|$? Sep12 asked Prove rigorously: $\displaystyle \lim_{x\rightarrow 2}x^2+5x=14$ Sep11 accepted Derivative at 4, when $f(x)=\frac{1}{\sqrt{2x+1}}$ Sep11 comment Derivative at 4, when $f(x)=\frac{1}{\sqrt{2x+1}}$ There was an error in my question (wrong function). This is relevant. Sorry for the confusion Sep11 comment Derivative at 4, when $f(x)=\frac{1}{\sqrt{2x+1}}$ yes there is an error. will fix in a moment Sep11 asked Derivative at 4, when $f(x)=\frac{1}{\sqrt{2x+1}}$ Sep10 accepted Speed of a bicycle wheel Sep10 accepted Evaluate the limit, if it exists Sep10 accepted Correct sigma notation for an equation that sums another equation