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 Mar17 comment Arc length of astroid $x^{-2/3} + 1$ though, right? Jan7 comment Pouring shampoo into a bottle at 16.5 cm³/s I gave as much info as the book gave me. I don't get the hold. I even included a photo and the questions that I had trouble answering, and the answers! Dec26 comment Is there an English translation of Diophantus's Arithmetica available? In Steven Hawking's "God Made the Integers" he has books II, III, and V, in English. Dec17 comment Derive a formula for the volume of the wedge in terms of the constants a, b, c. I'm having trouble connecting it to the 3rd dimension. Another similar triangle? Dec17 comment Derive a formula for the volume of the wedge in terms of the constants a, b, c. It is the vertical height from the $a$ line, parallel to $c$ Dec17 comment Derive a formula for the volume of the wedge in terms of the constants a, b, c. Yes I believe so. I see the way I'm doing it now is not working Dec13 comment What is $\sum_{n=1}^{\infty} \frac{n}{2^{\sqrt{n}}}$? well maybe forget L'Hôpital Dec13 comment What is $\sum_{n=1}^{\infty} \frac{n}{2^{\sqrt{n}}}$? Could L'Hôpital's rule be applied? It is infinity over infinity. ALso, according to wolfram alpha "lim x->infinity sum (x/(2^sqrt(x)))" returns $51.919191....$ Dec6 comment The minimum value of $\frac{a(x+a)^2}{\sqrt{x^2-a^2}}$ Oops. It was for an applied optimization problem. It didn't explicitly say "maximum," but I didn't want to include the extra info, just the derivative. I will edit Sep15 comment $\displaystyle \frac{d}{dx}2^x$ where $x=0$ @Shahar Yes {need more characters} Sep15 comment $\displaystyle \frac{d}{dx}2^x$ where $x=0$ @user164587 Haha, I hadn't ever noticed that. I'm in Calc 1 and we still use log as base 10 if not specified. And most, if not all calculators, naturally use base 10 Sep14 comment Prove rigorously: $\displaystyle \lim_{x\rightarrow 2}x^2+5x=14$ So it's like squaring both sides? (But multiplying by equivalents) Sep13 comment Prove rigorously: $\displaystyle \lim_{x\rightarrow 2}x^2+5x=14$ How did you find $|x-2||x+7|<(9+ \delta)\delta$? Sep12 comment Prove rigorously: $\displaystyle \lim_{x\rightarrow 2}x^2+5x=14$ $\delta>|x-2|$? Sep11 comment Derivative at 4, when $f(x)=\frac{1}{\sqrt{2x+1}}$ There was an error in my question (wrong function). This is relevant. Sorry for the confusion Sep11 comment Derivative at 4, when $f(x)=\frac{1}{\sqrt{2x+1}}$ yes there is an error. will fix in a moment Sep7 comment Simplifying compound fraction: $\frac{3}{\sqrt{5}/5}$ I know this an old question, but if you had simply changed your √5/5 to a √5/√5, you would've got 3√5÷5/5 and gotten your answer. The whole point of multiplying a complex faction by a number to simplify it is to times it by 1 (√5/√5 in this case) because multiplying anything by 1 is the same thing. Aug24 comment verify $\lim_{x\rightarrow0}(4x^2+2x+5)=5$ ok I think $|x||4x+2|$ is the answer my professor is looking for Aug23 comment verify $\lim_{x\rightarrow0}(4x^2+2x+5)=5$ We haven't gotten to delta-epsilon proofs yet Aug23 comment verify $\lim_{x\rightarrow0}(4x^2+2x+5)=5$ Actually that is in the next section of our book, on limit laws. We are not supposed to use those. But I see that that is an acceptable answer otherwise