412 reputation
216
bio website
location Berlin, Germany
age 25
visits member for 1 year, 8 months
seen yesterday

casting the runes

One of ICL's most talented systems designers used to be called out occasionally to service machines which the field circus had given up on. Since he knew the design inside out, he could often find faults simply by listening to a quick outline of the symptoms. He used to play on this by going to some site where the field circus had just spent the last two weeks solid trying to find a fault, and spreading a diagram of the system out on a table top.

He'd then shake some chicken bones and cast them over the diagram, peer at the bones intently for a minute, and then tell them that a certain module needed replacing. The system would start working again immediately upon the replacement.

The Jargon File, v4.4.7


Apr
16
accepted Average IQ of Mensa
Apr
12
awarded  Nice Question
Apr
11
awarded  Popular Question
Apr
11
asked Average IQ of Mensa
Feb
27
awarded  Popular Question
Feb
13
comment Limit of $\sqrt[x]{\frac{\tan x}{x}}$ as $x \to 0$
Using your method, what is $\left(\frac{\tan x}{x}\right)^\frac{1}{x^2}$ for $x \to 0$?
Feb
13
comment Limit of $\sqrt[x]{\frac{\tan x}{x}}$ as $x \to 0$
The power in my first example is $1/x$, in my second it's $1/x^2$. None of theam head to zero for $x \to 0$.
Feb
13
comment Limit of $\sqrt[x]{\frac{\tan x}{x}}$ as $x \to 0$
@DavidMitra: Using your argument, $(\tan x / x)^{1/x^2}$ should go to $1$ for $x \to 0$ as well. But it's $\sqrt[3]{e}$. See wolframalpha.com/input/…
Feb
13
accepted Limit of $\sqrt[x]{\frac{\tan x}{x}}$ as $x \to 0$
Feb
13
revised Limit of $\sqrt[x]{\frac{\tan x}{x}}$ as $x \to 0$
Replaced $\cos$ by $\sin$, because wrong. Does not change the results.
Feb
13
asked Limit of $\sqrt[x]{\frac{\tan x}{x}}$ as $x \to 0$
Feb
12
awarded  Notable Question
Feb
12
awarded  Nice Question
Feb
11
awarded  Popular Question
Feb
11
accepted Why are the rational numbers not continuous?
Feb
11
comment Why are the rational numbers not continuous?
@Martín-BlasPérezPinilla: My book ("Taschenbuch der Mathematik") states that "The set of real numbers is continuous, which means that every point on the number line has assigned a real number. This is not true for the rational numbers". How does one define this formally?
Feb
11
comment Why are the rational numbers not continuous?
But the holes are not included in the rational numbers. If I just define "apple" as $1 < \text{apple} < 2$, there is also a hole in the irrationals.
Feb
11
asked Why are the rational numbers not continuous?
Feb
9
awarded  Critic
Nov
21
revised Integral of $\sin(t)(1-\sin(t))^{3/2}$
Improved formatting