Polynomial
Reputation
Top tag
Next privilege 250 Rep.
 Apr 5 awarded Informed Dec 7 comment Solving a pair of equations across a data set Ah, ok. This whole thing was part of a weird crypto thing I was trying to solve, rather than a set problem. Dec 7 awarded Commentator Dec 7 accepted Solving a pair of equations across a data set Dec 7 comment Solving a pair of equations across a data set Brilliant. Solved my problem perfectly! :D Dec 7 comment Solving a pair of equations across a data set Sorry, I don't know what that means. Could you provide a worked example, please? Dec 7 comment Solving a pair of equations across a data set @robjohn You've lost me there. $k$ is unchanging across the data set. Dec 7 comment Solving a pair of equations across a data set I'm not sure how they're simultaneous, or how I'd re-write them. I'm sure you're correct, I just can't seem to visualise it. Dec 7 asked Solving a pair of equations across a data set Aug 1 comment Solving the “Library of Babel” puzzle, but for polygons. The number of polygons is arbitrary - one would include variable that as part of the solution. I also don't see how a polygon that has, essentially, two distinct points is valid - it's an infinitesimally thin line. Jul 30 comment Solving the “Library of Babel” puzzle, but for polygons. Very good point, I hadn't considered the problem of three points on the same line. That should certainly be disallowed. On the other hand, yes, two different polygons can share edges. The points are "randomly" chosen - the polygons may overlap, or share edges, share a single point, or they may be completely separate. The colours are an extension of the original idea of generating all possible images that could exist. Jul 30 asked Is $e$ uniformly distributed in all bases? Jul 30 asked Solving the “Library of Babel” puzzle, but for polygons. Jan 18 awarded Scholar Jan 18 accepted Moving the negative out of the integral - a bug in Wolfram Alpha? Jan 18 comment Moving the negative out of the integral - a bug in Wolfram Alpha? One thought is that $f(x)$ might be the reason it works, since it can't try to "optimise" with identities and other shortcuts. Jan 18 awarded Student Jan 18 asked Moving the negative out of the integral - a bug in Wolfram Alpha? Aug 1 awarded Supporter Aug 1 comment Solving $5^n > 4,000,000$ without a calculator @GerryMyerson The intent wasn't to pick on you, I was just joking. I actually upvoted you. The fact that you're dividing by two makes this a very good answer, because you have to take it to ridiculous extremes (like I did) before this method becomes implausible to use.