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Jan
12
answered construct triangle with $\hat C$ and length of the bisector of $\hat C$ and side c
Jan
5
comment Geometric derivation of the quadratic equation
@StellaBiderman see my edit, it will give you a sketch of a proof.
Jan
5
revised Geometric derivation of the quadratic equation
Giving a justification
Dec
26
revised Geometric derivation of the quadratic equation
added 18 characters in body
Dec
26
answered Geometric derivation of the quadratic equation
Dec
25
comment Geometric derivation of the quadratic equation
That is what you want: A geometric construction of the roots of a quadratic equation from the coordinates of the max/min point and the value of $a$?
Dec
24
awarded  Nice Answer
Dec
20
answered Need to find the ellipse of maximum area inscribed in a semicircle.
Dec
18
comment Need to find the ellipse of maximum area inscribed in a semicircle.
I used the coordinate based approach combined with calculus too. It took about $600$ cm² of paper area to solve it. Are you interested?
Dec
12
comment Calculate connecting line and circular arc between two points and angles
1.Do you have to connect always a straight track to a curved track with another straight track and curved track? 2. Is the straight track to be joined always vertical or horizontal, or can it assume any direction?
Dec
12
comment A better way to solve this question on Parabola?
@Sudhanshu I've used the same idea you had, but I used the intersection point of $L$ and $L_1$ and the $x$-intercept of $L1$. The advantage is that the mirror image of the intersection point is itself.
Dec
12
answered A better way to solve this question on Parabola?
Dec
9
comment Show that if $\angle ADB = 60^{\circ}$ then $AA_1 = BB_1$ (and answer whether the converse is true).
Let $m(\angle ADB) =90^{\circ}$ and $AD=DB$. Clearly $BB_1=AA_1$ and we don't have $m(\angle ADB) =60^{\circ}$.
Dec
9
comment Show that if $\angle ADB = 60^{\circ}$ then $AA_1 = BB_1$ (and answer whether the converse is true).
For $HA=HB$ and $HB_1=HA_1$ you got also isosceles triangles from the point of intersection.
Dec
9
comment Show that if $\angle ADB = 60^{\circ}$ then $AA_1 = BB_1$ (and answer whether the converse is true).
Are you sure that $HB_1=HA$? Couldn't it be that $HA=HB$?
Aug
27
awarded  Nice Answer
Aug
26
awarded  Necromancer
Jul
23
awarded  Yearling
Jul
10
comment How much heigth can a roll of pipe insulation cover?
50 ft² = 7200 in²
May
15
comment Three planes in general position, one point in each, construct sections
May we use a compass and a 1 unit line segment too?