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 Yearling
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Jul
23
awarded  Yearling
Jul
10
comment How much heigth can a roll of pipe insulation cover?
50 ft² = 7200 in²
Jul
5
comment Writing circles as $|z-a| = \lambda |z-b|$ for the same $a,b$
What have you tried?
May
15
comment Three planes in general position, one point in each, construct sections
May we use a compass and a 1 unit line segment too?
May
2
answered Construct the great circle (geodesic) in spherical or Riemanian geometry
May
1
comment Analytic Geometry - vectors and points
There is the same question and an answer here: math.stackexchange.com/questions/728383/…
Apr
19
comment Cabri 3D - Rotating a triangle
Are $T$ and $T_0$ given and you must find out the line $AB$?
Jan
9
comment Centroids and Harmonic Means
I think you mean one of them is HALF of the harmonic mean of the others. Don't you?
Jan
6
comment In the regular hexagon tell each area,But How find this length with $B_{i}B_{i+1}$?
@HandeBruijn Very good. It's really astonishing to get an exact answer. +1.
Jan
6
comment In the regular hexagon tell each area,But How find this length with $B_{i}B_{i+1}$?
@HandeBruijn Check the value of $x$. $x$ is not $45.27468489$.
Jan
5
comment In the regular hexagon tell each area,But How find this length with $B_{i}B_{i+1}$?
$x$ cannot be more than $2*A_1A_2$.
Dec
27
comment In the regular hexagon tell each area,But How find this length with $B_{i}B_{i+1}$?
If the hexagon were regular, then its total area $A$ should be: $A=6 \frac{L^2 \sqrt{3}}{4}$. As $L= |A_1A_2|=15$ , the area should be $A=\frac{675 \sqrt{3}}{2}$, but adding up all the given areas we get 15210?!
Dec
26
comment Finding Locus of a Midpoint of a Chord
@Pakquebchsoflwty By the converse of Thales Theorem the circle whose diameter is $OY$ is unique and $M$ is a point of this circle.The "lowest" position where $M$ can be is when $C$ is on $A$ or on $B$.In this case the smaller square becomes a point and the bigger square has its center on $Y$. $M$ will be the midpoint of $DC$ or $EC$ and $M$ will be a point of the perpendicular bisector of $YO$. Therefore $M$ is a point of the upper half semicircle. – RicardoCruz 1 hour ago
Dec
26
answered Finding Locus of a Midpoint of a Chord
Dec
23
awarded  Informed
Dec
20
comment Geometry construction problem
@RoryDaulton You're welcome. I'm happy to help.
Dec
20
comment Geometry construction problem
There is something that doesn't fit in the equation you got. I think the second term of the RHS should be $2 \sqrt{r^2-(d-z)^2}$. If you correct it, you will get a quadratic equation.
Dec
19
awarded  Constituent
Dec
18
comment Construct quadrangle with given angles and perpendicular diagonals
@HandeBruijn Since the OP wanted a compass-and-straightedge construction I thought it would be easier use equation(4) as it is. But it is possible to use another method (a graphical or algebraic one) to solve equation (4).
Dec
17
revised Construct quadrangle with given angles and perpendicular diagonals
added 6 characters in body