RicardoCruz
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 Jan 12 answered construct triangle with $\hat C$ and length of the bisector of $\hat C$ and side c Jan 5 comment Geometric derivation of the quadratic equation @StellaBiderman see my edit, it will give you a sketch of a proof. Jan 5 revised Geometric derivation of the quadratic equation Giving a justification Dec 26 revised Geometric derivation of the quadratic equation added 18 characters in body Dec 26 answered Geometric derivation of the quadratic equation Dec 25 comment Geometric derivation of the quadratic equation That is what you want: A geometric construction of the roots of a quadratic equation from the coordinates of the max/min point and the value of $a$? Dec 24 awarded Nice Answer Dec 20 answered Need to find the ellipse of maximum area inscribed in a semicircle. Dec 18 comment Need to find the ellipse of maximum area inscribed in a semicircle. I used the coordinate based approach combined with calculus too. It took about $600$ cm² of paper area to solve it. Are you interested? Dec 12 comment Calculate connecting line and circular arc between two points and angles 1.Do you have to connect always a straight track to a curved track with another straight track and curved track? 2. Is the straight track to be joined always vertical or horizontal, or can it assume any direction? Dec 12 comment A better way to solve this question on Parabola? @Sudhanshu I've used the same idea you had, but I used the intersection point of $L$ and $L_1$ and the $x$-intercept of $L1$. The advantage is that the mirror image of the intersection point is itself. Dec 12 answered A better way to solve this question on Parabola? Dec 9 comment Show that if $\angle ADB = 60^{\circ}$ then $AA_1 = BB_1$ (and answer whether the converse is true). Let $m(\angle ADB) =90^{\circ}$ and $AD=DB$. Clearly $BB_1=AA_1$ and we don't have $m(\angle ADB) =60^{\circ}$. Dec 9 comment Show that if $\angle ADB = 60^{\circ}$ then $AA_1 = BB_1$ (and answer whether the converse is true). For $HA=HB$ and $HB_1=HA_1$ you got also isosceles triangles from the point of intersection. Dec 9 comment Show that if $\angle ADB = 60^{\circ}$ then $AA_1 = BB_1$ (and answer whether the converse is true). Are you sure that $HB_1=HA$? Couldn't it be that $HA=HB$? Aug 27 awarded Nice Answer Aug 26 awarded Necromancer Jul 23 awarded Yearling Jul 10 comment How much heigth can a roll of pipe insulation cover? 50 ft² = 7200 in² May 15 comment Three planes in general position, one point in each, construct sections May we use a compass and a 1 unit line segment too?