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network profile
| bio | website | |
|---|---|---|
| location | ||
| age | ||
| visits | member for | 10 months |
| seen | 22 hours ago | |
| stats | profile views | 106 |
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23h |
answered | Gravitational fields |
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May 11 |
comment |
A construction using straightedge and compass @rschwieb , see my solution below. |
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May 11 |
revised |
A construction using straightedge and compass deleted 6 characters in body |
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May 11 |
answered | A construction using straightedge and compass |
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May 11 |
awarded | Caucus |
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Jan 28 |
revised |
Show that $x^{8}+5x^{2}=1$ has exactly $2$ real roots fixed grammar, improved formatting |
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Jan 28 |
answered | Show that $x^{8}+5x^{2}=1$ has exactly $2$ real roots |
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Jan 27 |
comment |
Reflection of a line on complex plane @K.Stm The problem is in both translations. First subtract $\frac{c}{a}$ and at last add $\frac{c}{a}$. |
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Jan 27 |
comment |
Constructing a triangle given three concurrent cevians? @F'Ola. Did that answer help you in anyway? |
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Jan 26 |
answered | What will be the slope of $BC$? |
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Jan 26 |
asked | Eliminating $\theta$ from the system |
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Jan 25 |
revised |
Constructing a triangle given three concurrent cevians? fixed grammar |
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Jan 25 |
answered | Constructing a triangle given three concurrent cevians? |
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Jan 16 |
answered | Different ways to work out the normal in the Frenet frame |
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Jan 13 |
answered | a geometry problem about inscribed and circumscribed circle radius. |
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Jan 12 |
comment |
I am trying to solve the inequality $\log_{\log{\sqrt{9-x^2}}} x^2 <0$ @Ahmed. You're welcome:) |
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Jan 12 |
answered | Polynomial approximation of circle or ellipse |
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Jan 11 |
answered | I am trying to solve the inequality $\log_{\log{\sqrt{9-x^2}}} x^2 <0$ |
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Jan 11 |
comment |
How can I find the curves in the problem? @zjk. As regards to the figure, it was drawn using Geogebra. |
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Jan 11 |
comment |
How can I find the curves in the problem? @zjk. As regards to $\dfrac{d \vec {r}}{d \theta}$, if you define two points $M$ and $M'$ as $M = O + \vec {r}(\theta)$ and $M' = O + \vec{r}(\theta + \Delta \theta)$ you will get a straight line defined by $MM'$ which is a secant line of the curve $\rho = f(\theta)$. When $\Delta \theta \to 0$, then $M' \to M$ and the line defined by $MM'$ approaches to a tangent line. So if you calculate $\dfrac {d \vec{r}}{d \theta} = \lim_{\Delta \theta \to 0}\frac{\vec {r}(\theta + \Delta \theta)-\vec {r}(\theta)}{\Delta \theta}$, you will ge a tangent vector to the curve at point $M$. |
