meta user
network profile
| bio | website | stackoverflow.com/users/… |
|---|---|---|
| location | Charlottesville, VA | |
| age | 20 | |
| visits | member for | 10 months |
| seen | Apr 17 at 4:43 | |
| stats | profile views | 116 |
I'm a 20 year old third-year at the University of Virginia. I am majoring in Systems Engineering with minors in Applied Mathematics and Computer Science. I am very familiar and experienced with Excel formulas, and I know Java, some C++ and SQL, and basic HTML and PHP. I am currently in the process of learning VBA. I play golf and follow professional golf rather intensively.
|
Aug 18 |
accepted | Random Walk Expected Number of Visits |
|
Aug 18 |
comment |
Random Walk Expected Number of Visits Ah okay, that makes sense. Thanks for your help! |
|
Aug 18 |
comment |
Random Walk Expected Number of Visits So if it were the case that both A and E were destination states, the answer to the question: Suppose a walker starts in vertex C. What is the expected number of visits to B before the walker reaches A? would come from the same matrix as the question: Suppose a walker starts in vertex C. What is the expected number of visits to B before the walker reaches E? |
|
Aug 18 |
comment |
Random Walk Expected Number of Visits First, you are absolutely right about the minus signs. I somehow convinced myself that $$0 - \frac{1}{3} = \frac{1}{3}.$$ And to be clear, that (C, B)th entry of the matrix M accounts for the fact that our destination is vertex A, right? And that would be because we designated A as an absorbing state? |
|
Aug 18 |
asked | Random Walk Expected Number of Visits |
|
Aug 13 |
comment |
Invariant Probability Vector Yep, that's exactly what I know how to do. You've been very helpful; thanks again! |
|
Aug 13 |
awarded | Student |
|
Aug 12 |
awarded | Scholar |
|
Aug 12 |
comment |
Invariant Probability Vector The first part of your response makes sense, but before reading this book I'd never heard the term left eigenvector. I took Linear Algebra a year ago so I can find the eigenvalue, but I couldn't tell you how to find the left eigenvector. |
|
Aug 12 |
comment |
Invariant Probability Vector Ahh this makes so much more sense now. Thank you! |
|
Aug 12 |
accepted | Invariant Probability Vector |
|
Aug 12 |
asked | Invariant Probability Vector |
|
Jul 30 |
awarded | Supporter |
|
Jul 27 |
comment |
hints on solving $ \sin^2 x {d^2y \over dx^2} = 2 y$ Another way to come by what @PeterTamaroff got is by using double angle formulas. $$cos(2x) + 1 = 2cos^2(x)$$ $$sin(2x) = 2sin(x)cos(x)$$ Substituting these in will yield the correct answer. |
|
Jul 24 |
awarded | Teacher |
|
Jul 24 |
answered | Possible distance b/w points |
|
Jul 20 |
comment |
Survival function Are you looking for the median or the mean? |
|
Jul 20 |
reviewed | Approve suggested edit on Find value of K in matrix |
|
Jul 20 |
answered | Find value of K in matrix |
|
Jul 20 |
comment |
Find value of K in matrix Need to reformat the matrices. I would, but I'm brand new here and don't know how. |
