Magpie

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I tend to break things.

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Integral related to the modified Bessel function

integral special-functions

sep 13 at 2:57 Sasha 41.6k

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Evaluating $\int_0^1{\frac{1}{(x+3)^2}}\ln\left(\frac{x+1}{x+3}\right)dx$ using $\frac{dy}{dx}=\frac{2}{(x+3)^2}$ where $y=\frac{x+1}{x+3}$

calculus integral definite-integral

aug 10 at 20:36 Magpie 278

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