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I am a high school student interested in mathematics.


Apr
9
comment Prove that if b is coprime to 6 then $b^2 \equiv 1 $ (mod 24)
Since $b^2$ is a perfect square, we have that $b^2 = 1,4,9,16$ modulo $24$. All of these, besides $1$, require that $2 | b$ or $3 | b$.
Mar
9
comment Is this fraction even possible to put into partial fractions?
@Wolff Think inverse trigonometric functions.
Feb
6
comment Real Analysis Question concerning existence of curve and derivative?
Suppose $f(0) \ne 0$. Use continuity of $f$ to obtain a contradiction.
Jan
31
comment % of my equivalent human life hunting a fly for 5 minutes before I kill it, if its lived for 3 days and myself for 40 years
House flies usually live for 15 to 30 days once hatched from pupal stage, though you may very well have been chasing a 3-day-old fly.
Jan
31
answered How to find the inverse function?
Jan
24
comment Does an element of a group to the 0th power equal the identity?
In other words, the assignment of $x^0 = 1$ plays nice with $x^ax^b = x^{ab}$ for all $a$ and $b$, a desirable property.
Jan
19
comment Does this equation have positive integer solutions?
In other words, combining any two Pythagorean triples gives a solution.
Jan
5
comment How do I show using math symbols “get quotient without remainder”
Try $\lfloor 10/3 \rfloor=3$. This is the "floor" operation and gets rid of any decimal.
Jan
2
comment How find this integral
Your bounds are for $t$, but you treated them as if they were for $\theta$. Notice that $\theta = \sin^{-1} t$, so you can easily switch back.
Dec
31
answered How many even numbers are there in a set $\{x_1, x_2 … x_n\}$
Dec
30
answered The number of ways in which 6 pencils can be distributed between two boys such that each boy gets at least one pencil is
Dec
29
revised Project Euler - 34 / Find a mathematical approach for upper bound
deleted 8 characters in body
Dec
29
revised Project Euler - 34 / Find a mathematical approach for upper bound
added 294 characters in body
Dec
29
answered Project Euler - 34 / Find a mathematical approach for upper bound
Dec
27
revised Don't be Greedier
added 546 characters in body
Dec
27
answered Don't be Greedier
Dec
27
comment Don't be Greedier
If a player removes one pebble when there is an odd number of pebbles remaining, that player wins.
Dec
27
awarded  Enthusiast
Dec
27
comment Don't be Greedier
What have you tried?
Dec
27
awarded  Citizen Patrol