meta user
network profile
| bio | website | |
|---|---|---|
| location | North Carolina | |
| age | 18 | |
| visits | member for | 11 months |
| seen | Apr 22 at 14:07 | |
| stats | profile views | 24 |
I am a high school student with a passion for math. I'm trying to get some exposure to mathematics aside from what I can get at school (although I am fortunate enough to attend a school with a number of courses beyond basic calculus).
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Jul 19 |
comment |
Why do we say the harmonic series is divergent? I certainly intended no offense, and I regret that my wording offended you. As @did says, I was simply checking your understanding, as your second sentence seems to imply (to me) that any constantly increasing series is divergent regardless of whether it tends to infinity at the limit. We can answer most usefully and clearly if we know whether to focus on the terminology or the proof. I hope there are no hard feelings. |
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Jul 18 |
answered | Why do these two methods of calculating the probability of winning a best-of-7 series give the same answer? |
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Jul 18 |
awarded | Commentator |
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Jul 18 |
awarded | Critic |
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Jul 18 |
comment |
Determine if it is possible to fit 2 circles in a rectangle Unless I misunderstand, shouldn't it be $d[(r_1,r_1), (l-r_2,h-r_2)] \geq r_1+r_2$? |
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Jul 18 |
revised |
Swatting flies with a sledgehammer Fixed typo in title |
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Jul 18 |
suggested | suggested edit on Swatting flies with a sledgehammer |
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Jul 18 |
comment |
Why do we say the harmonic series is divergent? Do you know what the word "divergent" means here? |
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Jul 18 |
awarded | Editor |
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Jul 18 |
revised |
How many rolls until probability of a 5 is at least 1/2? improved clarity |
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Jul 18 |
comment |
How many rolls until probability of a 5 is at least 1/2? That would be the probability of rolling a $5$ every time. An event of probability $P$ occurring $n$ times in a row has probability $P^n$, and the probability of the complement (opposite) of $P$ occurring during $n$ trials is $1-P^n$. |
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Jul 18 |
answered | How many rolls until probability of a 5 is at least 1/2? |
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Jul 16 |
comment |
Solve for $a$: $V=2(ab+bc+ca)$ Not quite; perhaps I've not explained my hint clearly. Try it this way: I see you refer to "take out the a". Do this from your (correct) expression $\left(\frac{V}{2}\right)-bc=ab+ca$. |
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Jul 16 |
comment |
Solve for $a$: $V=2(ab+bc+ca)$ Since you did that one step forwards and then backwards and got something different, you know that you did something wrong there. If you distribute your $2a$ in what you just wrote, you get $\left(\frac{V}{2}\right)-bc=2ab+2ca$. This is very close to what it should be, but the right is a bit different - there's an extra factor of $2$ on each term. That should tell you what you did wrong. |
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Jul 16 |
comment |
Solve for $a$: $V=2(ab+bc+ca)$ By backwards, I mean take your expression $\dfrac{\left(\frac{V}{2}\right)-bc}{b+c}=2a$ and multiply it by $b+c$. Do you get the expression you had before you divided by $b+c$? |
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Jul 16 |
answered | Solve for $a$: $V=2(ab+bc+ca)$ |
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Jul 14 |
answered | Does $\sum_{n\ge1} \sin (\pi \sqrt{n^2+1}) $ converge/diverge? |
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Jul 14 |
answered | Counting zero-digits between 1 and 1 million |
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Jul 13 |
comment |
How to prove $p$ divides $a^{p - 2} + a^{p - 3} b + a^{p - 4} b^2 + \cdots + b^{p - 2}$ when $p$ is prime, $a, b \in \mathbb{Z}$ and $a,b \lt p$? Do a and b need to be distinct? Else it seems to me that a=1, b=1, p=3 is a counterexample unless I misunderstand something. |
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Jul 13 |
answered | Can two sets have same AM, GM, HM? |
