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Oct
18
comment Square root of continued fraction
That doesn't answer my question. Note that the question is in the first paragraph; there's a reason the second paragraph begins with "For example".
Oct
18
revised Square root of continued fraction
edited tags; edited tags
Oct
18
asked Square root of continued fraction
Oct
12
comment Let $T:\mathcal{P}(\mathbb{R})\to \mathcal{P}(\mathbb{R})$ such that $T(p)=p-p'$. Find all eigen values and eigen vectors of $T$.
Ah, I understand, you interpret "$p'$" as "derivative of $p$". I interpreted it as some constant value independent of $p$ that is also a polynomial. Which shows how important it is to properly specify the problem. :-)
Oct
12
comment Let $T:\mathcal{P}(\mathbb{R})\to \mathcal{P}(\mathbb{R})$ such that $T(p)=p-p'$. Find all eigen values and eigen vectors of $T$.
I don't see anything stating a specific degree of $p'$.
Oct
12
comment Let $T:\mathcal{P}(\mathbb{R})\to \mathcal{P}(\mathbb{R})$ such that $T(p)=p-p'$. Find all eigen values and eigen vectors of $T$.
What about $p=\alpha p'$?
Oct
11
awarded  Inquisitive
Oct
10
comment Two spaces contain the same vector, can we say the space with smaller dimension is a subspace of the larger one?
@peter: See edit
Oct
10
revised Two spaces contain the same vector, can we say the space with smaller dimension is a subspace of the larger one?
edited to make all entries of alpha and beta positive
Oct
10
answered Two spaces contain the same vector, can we say the space with smaller dimension is a subspace of the larger one?
Oct
10
comment What is the right way to define a function?
See en.wikipedia.org/wiki/…
Oct
10
accepted Deriving topology from sequence convergence/limits?
Oct
10
asked Deriving topology from sequence convergence/limits?
Oct
10
comment Greatest integer less than or equal to $x^*$
I guess some of your $x^*$ should have been just $x$.
Oct
10
comment On the proof that for $0<x<1$ there exists a real number $a$ s.t. $x^n < a$
But for any $a\in (0,1)$ and any $n$ you will find an $x$ so that $x^n > a$ (for example, $x = \left(\frac{1+a}{2}\right)^{1/n}$). Thus an $a$ that doesn't depend on $x$ cannot be found in that case.
Oct
10
comment On the proof that for $0<x<1$ there exists a real number $a$ s.t. $x^n < a$
Shouldn't the (independent of $n$) choice $a=1$ always work?
Oct
10
comment Definition of “simplify”
"I don't know if anyone's ever tried to define "simple" in any objective way," — computer algebra systems usually contain a simplify function; that certainly needs to use an objective metric. Of course the "simpler" expressions don't necessarily look simpler to the human looking at them (for example, Mathematica thinks that $(-1+x)^2$ is simpler than $(1-x)^2$).
Oct
9
comment Determine whether a function can be extended
What about the path $\alpha=\theta^m$? Then $\theta^m/\alpha = 1$ for every $\theta\ne 0$, and therefore the limit along this path is $1$ for $\theta\to 0$.
Oct
9
revised Determine whether a function can be extended
fixed MathJax formatting
Oct
9
revised Why does $\sqrt{2x+15}-6=x$ have an “imposter” solution?
added 26 characters in body