Quispiam
Reputation
498
Next privilege 500 Rep.
Access review queues
 Aug 25 accepted Finding all $x$ for $\frac{2x - 13}{2x + 3} \lt \frac{15}{x}$ Aug 25 asked Finding all $x$ for $\frac{2x - 13}{2x + 3} \lt \frac{15}{x}$ Aug 24 accepted How to find $k$'s quotient of $\frac{-18}{(-2)^k}$ Aug 24 comment How to find $k$'s quotient of $\frac{-18}{(-2)^k}$ Thank you, I see now. But don't you mean $\frac{a(r^{n+1}-1)}{r-1}$? Or am I mistaken? Aug 24 asked How to find $k$'s quotient of $\frac{-18}{(-2)^k}$ Aug 24 accepted Getting wrong result calculating sums Aug 24 comment Getting wrong result calculating sums I can't believe I missed such a simple mistake. Thank you! Aug 24 asked Getting wrong result calculating sums Aug 20 accepted Finding a value for $x$ when there should be none Aug 20 comment Finding a value for $x$ when there should be none @AndréNicolas Ah, yes, I see. Thank you. Aug 20 comment Finding a value for $x$ when there should be none @AndréNicolas You mean dividing by $0$? Aug 20 comment Finding a value for $x$ when there should be none This is the second time in a row I've been stuck on a problem simply because I forgot about the zero-divide no-no. :/ Thanks. Aug 20 asked Finding a value for $x$ when there should be none Aug 18 comment Calculating $x$ from $x^3 = 2x^2 - x$, getting wrong result Thanks! It never struck me that $x$ could be $0$ and that I discounted that possibility so easily. Aug 18 accepted Compute integral $\int_{-6}^6 \! \frac{(4e^{2x} + 2)^2}{e^{2x}} \, \mathrm{d} x$ Aug 18 accepted Getting square root of negative in completing the square problem Aug 18 accepted Calculating $x$ from $x^3 = 2x^2 - x$, getting wrong result Aug 18 comment Calculating $x$ from $x^3 = 2x^2 - x$, getting wrong result I did actually try $x=1$ in the original equation, but were confused as I was supposed to find two separate for $x$. I didn't even stop to think it could be $0$. Thanks! Aug 18 asked Calculating $x$ from $x^3 = 2x^2 - x$, getting wrong result Aug 18 revised Getting square root of negative in completing the square problem nvm