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 Aug24 accepted How to find $k$'s quotient of $\frac{-18}{(-2)^k}$ Aug24 comment How to find $k$'s quotient of $\frac{-18}{(-2)^k}$ Thank you, I see now. But don't you mean $\frac{a(r^{n+1}-1)}{r-1}$? Or am I mistaken? Aug24 asked How to find $k$'s quotient of $\frac{-18}{(-2)^k}$ Aug24 accepted Getting wrong result calculating sums Aug24 comment Getting wrong result calculating sums I can't believe I missed such a simple mistake. Thank you! Aug24 asked Getting wrong result calculating sums Aug20 accepted Finding a value for $x$ when there should be none Aug20 comment Finding a value for $x$ when there should be none @AndréNicolas Ah, yes, I see. Thank you. Aug20 comment Finding a value for $x$ when there should be none @AndréNicolas You mean dividing by $0$? Aug20 comment Finding a value for $x$ when there should be none This is the second time in a row I've been stuck on a problem simply because I forgot about the zero-divide no-no. :/ Thanks. Aug20 asked Finding a value for $x$ when there should be none Aug18 comment Calculating $x$ from $x^3 = 2x^2 - x$, getting wrong result Thanks! It never struck me that $x$ could be $0$ and that I discounted that possibility so easily. Aug18 accepted Compute integral $\int_{-6}^6 \! \frac{(4e^{2x} + 2)^2}{e^{2x}} \, \mathrm{d} x$ Aug18 accepted Getting square root of negative in completing the square problem Aug18 accepted Calculating $x$ from $x^3 = 2x^2 - x$, getting wrong result Aug18 comment Calculating $x$ from $x^3 = 2x^2 - x$, getting wrong result I did actually try $x=1$ in the original equation, but were confused as I was supposed to find two separate for $x$. I didn't even stop to think it could be $0$. Thanks! Aug18 asked Calculating $x$ from $x^3 = 2x^2 - x$, getting wrong result Aug18 revised Getting square root of negative in completing the square problem nvm Aug18 revised Getting square root of negative in completing the square problem Mixed up a + and - on $\frac{7}{4}$ (doesn't affect the outcome). Aug17 asked Getting square root of negative in completing the square problem