Quispiam
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 Sep 13 asked Finding $\alpha$ for $\sin(4 \alpha + \frac{\pi}{6}) = \sin (2\alpha + \frac{\pi}{5})$ Sep 13 accepted $\sin 4\alpha = 2\sin 2\alpha \times \cos 2\alpha$? Sep 13 asked $\sin 4\alpha = 2\sin 2\alpha \times \cos 2\alpha$? Sep 13 asked Two unrelated equations, $w^2 = -\frac{15}{4} - 2i$ and $z^2 - (3-4i)z + (2-4i) = 0$? Sep 12 comment Calculate $\cos(v+\frac{\pi}{6})$ when $\cos v = -\frac{2}{3}$ This helped a lot, I found the answer and it seems to be correct ($-\frac{2\sqrt{3}+\sqrt{5}}{6}$). Thank you! Sep 12 accepted Calculate $\cos(v+\frac{\pi}{6})$ when $\cos v = -\frac{2}{3}$ Sep 12 asked Calculate $\cos(v+\frac{\pi}{6})$ when $\cos v = -\frac{2}{3}$ Sep 10 accepted Finding highest possible value of function Sep 10 revised Finding highest possible value of function p(t), not t Sep 10 asked Finding highest possible value of function Sep 4 accepted Calculating the chess problem, sum $\sum_{k=0}^{63}2^{k}$ Aug 30 comment Calculating the chess problem, sum $\sum_{k=0}^{63}2^{k}$ Discovered my mistake - it was supposed to be $2^{64} - 1$, not $2^{64} + 1$. Aug 30 asked Calculating the chess problem, sum $\sum_{k=0}^{63}2^{k}$ Aug 29 accepted Calculate absolute values with unknown constant Aug 26 asked Calculate absolute values with unknown constant Aug 25 comment Finding all $x$ for $\frac{2x - 13}{2x + 3} \lt \frac{15}{x}$ It seems I figured everything out now. It was part of a bigger problem (uniting it with another inequality) and it seems like everything goes together perfectly now. Thanks a lot for the help. Aug 25 comment Finding all $x$ for $\frac{2x - 13}{2x + 3} \lt \frac{15}{x}$ Sorry, that was me being too excited after suddenly getting things right for once. Should have kept checking for roots after finding the obvious one. Thank you. Aug 25 comment Finding all $x$ for $\frac{2x - 13}{2x + 3} \lt \frac{15}{x}$ Thank you! Calculating for case (2) I find the root $-1$ for $2x^2 - 43x - 45$. Adding this to the roots of $2x(x+\frac{3}{2})$, this should mean that the entire expression is negative when $\frac{-3}{2} \lt x \lt -1$ or $0 \lt x$. However, when testing higher numbers (approximately where $x \gt 22$), $2x^2 - 43x - 45$ becomes positive and so the entire expression becomes positive. Why is this? Aug 25 awarded Commentator Aug 25 comment Finding all $x$ for $\frac{2x - 13}{2x + 3} \lt \frac{15}{x}$ Thank you. Correction, though - the $45$ should be negative.