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Sep
12
asked Calculate $\cos(v+\frac{\pi}{6})$ when $\cos v = -\frac{2}{3}$
Sep
10
accepted Finding highest possible value of function
Sep
10
revised Finding highest possible value of function
p(t), not t
Sep
10
asked Finding highest possible value of function
Sep
4
accepted Calculating the chess problem, sum $\sum_{k=0}^{63}2^{k}$
Aug
30
comment Calculating the chess problem, sum $\sum_{k=0}^{63}2^{k}$
Discovered my mistake - it was supposed to be $2^{64} - 1$, not $2^{64} + 1$.
Aug
30
asked Calculating the chess problem, sum $\sum_{k=0}^{63}2^{k}$
Aug
29
accepted Calculate absolute values with unknown constant
Aug
26
asked Calculate absolute values with unknown constant
Aug
25
comment Finding all $x$ for $\frac{2x - 13}{2x + 3} \lt \frac{15}{x}$
It seems I figured everything out now. It was part of a bigger problem (uniting it with another inequality) and it seems like everything goes together perfectly now. Thanks a lot for the help.
Aug
25
comment Finding all $x$ for $\frac{2x - 13}{2x + 3} \lt \frac{15}{x}$
Sorry, that was me being too excited after suddenly getting things right for once. Should have kept checking for roots after finding the obvious one. Thank you.
Aug
25
comment Finding all $x$ for $\frac{2x - 13}{2x + 3} \lt \frac{15}{x}$
Thank you! Calculating for case (2) I find the root $-1$ for $2x^2 - 43x - 45$. Adding this to the roots of $2x(x+\frac{3}{2})$, this should mean that the entire expression is negative when $\frac{-3}{2} \lt x \lt -1$ or $0 \lt x$. However, when testing higher numbers (approximately where $x \gt 22$), $2x^2 - 43x - 45$ becomes positive and so the entire expression becomes positive. Why is this?
Aug
25
awarded  Commentator
Aug
25
comment Finding all $x$ for $\frac{2x - 13}{2x + 3} \lt \frac{15}{x}$
Thank you. Correction, though - the $45$ should be negative.
Aug
25
accepted Finding all $x$ for $\frac{2x - 13}{2x + 3} \lt \frac{15}{x}$
Aug
25
asked Finding all $x$ for $\frac{2x - 13}{2x + 3} \lt \frac{15}{x}$
Aug
24
accepted How to find $k$'s quotient of $\frac{-18}{(-2)^k}$
Aug
24
comment How to find $k$'s quotient of $\frac{-18}{(-2)^k}$
Thank you, I see now. But don't you mean $\frac{a(r^{n+1}-1)}{r-1}$? Or am I mistaken?
Aug
24
asked How to find $k$'s quotient of $\frac{-18}{(-2)^k}$
Aug
24
accepted Getting wrong result calculating sums