Joebevo
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 Apr 25 asked Should the sign be reversed if I square both sides of an inequality? Apr 7 awarded Tumbleweed Apr 2 accepted Is 440 a factor of 72840? Apr 2 asked Is 440 a factor of 72840? Apr 2 asked Finding mean of $n$ consecutive numbers using a shortcut Apr 1 accepted Find the median given a table of relative frequencies Mar 31 comment Find the median given a table of relative frequencies I'm curious -- why do you think it should be zero? I don't see that. Mar 31 asked Find the median given a table of relative frequencies Mar 30 asked Finding a number given its remainder when divided by other numbers Mar 11 asked Showing that $\operatorname{div}\Psi\nabla\Psi^*-\operatorname{div}\Psi^*\nabla\Psi=\operatorname{div}[\Psi\nabla\Psi^*-\Psi^*\nabla\Psi]$ Dec 7 comment Solving the time-independent Schrodinger equation for particle in a potential well Ah, careless.. thanks. Dec 7 asked Solving the time-independent Schrodinger equation for particle in a potential well Nov 28 revised Manipulating derivatives after substitution: $\xi=\gamma x$ added 29 characters in body Nov 28 answered Manipulating derivatives after substitution: $\xi=\gamma x$ Nov 28 revised Manipulating derivatives after substitution: $\xi=\gamma x$ Added further attempt at problem Nov 28 accepted Showing that $\langle p\rangle=\int\limits_{-\infty}^{+\infty}p |a(p)|^2 dp$ Nov 28 asked Manipulating derivatives after substitution: $\xi=\gamma x$ Nov 22 comment Showing that $\langle p\rangle=\int\limits_{-\infty}^{+\infty}p |a(p)|^2 dp$ Thanks for your clarifications. That takes care of the $a(p')$. But what about the $p'$ becoming a $p$? Nov 22 comment Showing that $\langle p\rangle=\int\limits_{-\infty}^{+\infty}p |a(p)|^2 dp$ Yes, but in the penultimate step, you have both $a(p)^*$ and $a(p)$ being integrated over $p$. This seems contrary to step 2, where $a(p)^*$ goes with $p$ and $a(p')$ with $p'$. So shouldn't your penultimate step read $\int_{-\infty}^{\infty} p' a(p)^*a(p') \, dp$? Nov 22 comment Modulus of a complex function: $\Psi(x)=A_0 e^{-kx^2} e^{i\alpha x}$ It seems to work, and I'll make a note of it in my notes, but I just wanted to make sure that it's the most general way to find the modulus. Somehow, I seem to have missed the class where they extended the idea of a modulus to cover complex functions. It's like a secret that everybody is in on except me!