Reputation
3,788
Top tag
Next privilege 5,000 Rep.
Approve tag wiki edits
 Dec24 awarded Great Answer Dec21 awarded Popular Question Dec20 awarded algebra-precalculus Dec11 revised Find the Viète formula added 332 characters in body Dec11 answered Find the Viète formula Oct16 answered Integrate $\csc(x)^3dx$ Sep30 awarded Explainer Sep8 awarded Tumbleweed Sep8 answered Integral of $x^2 \cos(a x)\; \mathrm{d}x$ Sep1 asked Prove the property of the theorem Aug20 answered Evaluate $\int\frac{\sqrt{9-x^2}}{x^2}\mathrm dx$ Aug8 answered If $A,B,C\in L(X)$ commutes, then $A\leq B,$ and $C\geq 0$ follows $AC\leq BC.$ Jul30 accepted Prove the equation $\vert d(x,z)-d(y,t)\vert\leq d(x,y)+d(z,t)$ Jul30 comment Prove the equation $\vert d(x,z)-d(y,t)\vert\leq d(x,y)+d(z,t)$ thanks sir, now I understood very well after your solution Jul30 comment Prove the equation $\vert d(x,z)-d(y,t)\vert\leq d(x,y)+d(z,t)$ thanku very much sir, Jul30 comment Prove the equation $\vert d(x,z)-d(y,t)\vert\leq d(x,y)+d(z,t)$ I now this inequlity, but but please help me with the necessary steps proving, thanks Jul30 asked Prove the equation $\vert d(x,z)-d(y,t)\vert\leq d(x,y)+d(z,t)$ Jul27 comment If there is the inverse operator of the operator A, then $(A^{-1})^{-1}=A$? can you please explain this to add to your solution to be more clear Jul27 comment If there is the inverse operator of the operator A, then $(A^{-1})^{-1}=A$? @ Jonas Meyer: i.e., The above solution is not correct Jul27 comment If there is the inverse operator of the operator A, then $(A^{-1})^{-1}=A$? thanks sir, please help me for the last part, it is easy to see that $AB≠I$.