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1d
awarded  Popular Question
2d
awarded  algebra-precalculus
Dec
11
revised Find the Viète formula
added 332 characters in body
Dec
11
answered Find the Viète formula
Oct
16
answered Integrate $\csc(x)^3dx $
Sep
30
awarded  Explainer
Sep
8
awarded  Tumbleweed
Sep
8
answered Integral of $x^2 \cos(a x)\; \mathrm{d}x$
Sep
1
asked Prove the property of the theorem
Aug
20
answered Evaluate $\int\frac{\sqrt{9-x^2}}{x^2}\mathrm dx$
Aug
8
answered If $A,B,C\in L(X)$ commutes, then $A\leq B,$ and $C\geq 0$ follows $AC\leq BC.$
Jul
30
accepted Prove the equation $\vert d(x,z)-d(y,t)\vert\leq d(x,y)+d(z,t)$
Jul
30
comment Prove the equation $\vert d(x,z)-d(y,t)\vert\leq d(x,y)+d(z,t)$
thanks sir, now I understood very well after your solution
Jul
30
comment Prove the equation $\vert d(x,z)-d(y,t)\vert\leq d(x,y)+d(z,t)$
thanku very much sir,
Jul
30
comment Prove the equation $\vert d(x,z)-d(y,t)\vert\leq d(x,y)+d(z,t)$
I now this inequlity, but but please help me with the necessary steps proving, thanks
Jul
30
asked Prove the equation $\vert d(x,z)-d(y,t)\vert\leq d(x,y)+d(z,t)$
Jul
27
comment If there is the inverse operator of the operator A, then $(A^{-1})^{-1}=A$?
can you please explain this to add to your solution to be more clear
Jul
27
comment If there is the inverse operator of the operator A, then $(A^{-1})^{-1}=A$?
@ Jonas Meyer: i.e., The above solution is not correct
Jul
27
comment If there is the inverse operator of the operator A, then $(A^{-1})^{-1}=A$?
thanks sir, please help me for the last part, it is easy to see that $AB≠I$.
Jul
27
comment If there is the inverse operator of the operator A, then $(A^{-1})^{-1}=A$?
$A$ is a linear operator