Reputation
1,531
Top tag
Next privilege 2,000 Rep.
Edit questions and answers
Badges
1 13 39
Impact
~107k people reached

Nov
5
asked Limit of metric of sequences
Nov
4
awarded  Notable Question
Oct
31
asked Finding a nonzero continuous function that satisfies this integral equation, but not unique?
Sep
14
accepted Showing that $(a_n^2)$ is Cauchy implies that $(a_n)$ is Cauchy
Sep
8
comment Showing that $(a_n^2)$ is Cauchy implies that $(a_n)$ is Cauchy
Ah! Precisely, thank you André
Sep
8
asked Showing that $(a_n^2)$ is Cauchy implies that $(a_n)$ is Cauchy
Sep
3
awarded  Popular Question
Jul
20
awarded  Popular Question
Jun
29
awarded  Yearling
Jun
16
revised Checking an inductive proof on a combinatorial product
added 10 characters in body
Jun
16
comment Checking an inductive proof on a combinatorial product
@coffeemath when you say "yes" are you confirming that I do indeed have this right? I have added the $k \geq 2$ condition thanks for this input. Regards.
Jun
14
asked Checking an inductive proof on a combinatorial product
Jun
13
answered Introductory books on complex analysis?
Jun
13
comment Binomial coefficients equal to a prime squared
Never mind, I now see that you would need $2p \cdot (2p - 1) \cdots (p)(p-1)\cdots$. Thanks again
Jun
13
comment Binomial coefficients equal to a prime squared
I accepted Jyrki's answer, but I want to thank you for the referral to the paper, this is useful for the more general aspects of my project
Jun
13
comment Binomial coefficients equal to a prime squared
many thanks for this response. A neat proof! However I wonder if you could elaborate on why it is necessary that $2p \leq m$, and not the more trivial bound that $p^2 \leq m$?
Jun
13
accepted Binomial coefficients equal to a prime squared
Jun
12
asked Binomial coefficients equal to a prime squared
Jun
5
comment Trying to prove an identity about a product
I will go down that route, thanks for your suggestions @wece
Jun
5
comment Trying to prove an identity about a product
@wece I thought that I should induct on $p$ and then perhaps have a "nested" induction on $n$ inside the proof. How can I induct on $n$ but still establish that it is only those above tuples that give me the desired dimension?