KingOliver
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 Sep4 asked How to show that the $k$th return to $y$ is a stopping time Sep1 revised Proving that $a,n$ and $b, n$ relatively prime implies $ab,n$ relatively prime corrected question Sep1 accepted Proving that $a,n$ and $b, n$ relatively prime implies $ab,n$ relatively prime Sep1 suggested rejected edit on Which of the following subsets of $\mathbb{R}^2$ are compact Aug31 comment Proving that $a,n$ and $b, n$ relatively prime implies $ab,n$ relatively prime Sorry everyone! The body is a typo. I mean the $\gcd(ab,n) = 1$ Aug31 comment Proving that $a,n$ and $b, n$ relatively prime implies $ab,n$ relatively prime Well...this is embarrassing. Thanks! Aug31 asked Proving that $a,n$ and $b, n$ relatively prime implies $ab,n$ relatively prime Aug30 accepted Proof With and Without Truth Tables Aug30 asked Proof With and Without Truth Tables Aug27 accepted Proving lack of convergence in $\sup$-norm Aug27 comment Proving lack of convergence in $\sup$-norm Ah, thank you Ilya Aug27 accepted Checking Uniform Convergence Aug27 asked Proving lack of convergence in $\sup$-norm Aug26 comment Convergence in $\sup$ norm $\Rightarrow$ Cauchy in $\sup$ I see. So since $(f_n)$ is convergent, I have that for $\epsilon >0$ there is an $N$, respectively an $M$, so that for $n \ge N$, $m \ge M$, we have $\|f_n -f \|_{\infty} < {\epsilon \over 2}$ and $\|f_m -f \|_{\infty} < {\epsilon \over 2}$. Therefore we have $\|f_n - f_m\|_{\infty} < \epsilon$. Thank you for this succinct explanation Aug26 accepted Convergence in $\sup$ norm $\Rightarrow$ Cauchy in $\sup$ Aug26 asked Convergence in $\sup$ norm $\Rightarrow$ Cauchy in $\sup$ Aug25 comment Problem books in higher mathematics Abstract Algebra: amazon.com/Abstract-Algebra-Manual-Problems-Solutions/dp/… Aug25 answered Problem books in higher mathematics Aug24 accepted Proving pointwise convergence to a “Dirichlet-like” function Aug24 comment Proving pointwise convergence to a “Dirichlet-like” function @BenjaLim I think that is the point as to why it does not converge uniformly, but we can always take $n$ sufficiently large as to make the difference less than $\epsilon$. We list up to $n$ simply by AC I believe