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seen Jul 7 at 17:45

merge keep


Jul
2
awarded  Curious
Jun
13
comment Game theory problem… I think…
I couldn't find a free PDF of Stahl, but maybe you can have a look at Janssen et al. (2005), which directly builds on Stahl. See kelley.iu.edu/mwildenb/costlysearch.pdf
Jun
13
comment Game theory problem… I think…
And in particular, if all consumers have to pay a positive "fine" (search cost), the famous "Diamond paradox" (see Diamond 1971) arises: in equilibrium, both firms will charge the monopoly price for the good(s) they offer.
Jun
13
comment Game theory problem… I think…
You might want to consider reading Stahl (1989), one of the seminal articles in the literature on (sequential) consumer search in economics. I think his setup directly corresponds to the one you have in mind. See jstor.org/stable/1827927?__redirected
Feb
11
answered How to prove the open interval $(1,5)$ is a convex set?
Feb
10
comment How to solve $|x^2-1|-2\ge 2x$
Do you mean the two cases? This follows directly from the right hand side - it will be negative for $x < -1$ and positive for $x \geq -1$. Hence, for $x < -1$, the inequality is automatically fulfilled.
Feb
10
answered How to solve $|x^2-1|-2\ge 2x$
Dec
27
awarded  Yearling
Dec
27
answered Bob and Alice question
Nov
21
comment Need someone to quickly confirm whether I have this expected value correct
Looks correct to me. $E(Y^2)$ and $E(XY)$ are not needed for that answer, btw.
Nov
17
answered Can't isolate $x$ for this equation
Nov
13
comment Proving constant function given the second derivative.
$f(x) = x^2$ fulfills both criteria, but is not constant.
Oct
28
answered Difficult Derivative?
Oct
28
awarded  Tumbleweed
Oct
27
asked Finding a (tighter) sufficient condition on the standard deviation of a random variable
Oct
26
comment Proving that roots of a quadratic lie between two values
That's overall a nice answer, but to be 100% clean, I think it should read $x \in (x_1, x_2)$ (open instead of closed interval).
Oct
22
asked Functional optimization problem with constraint
Oct
21
asked Bounding the standard deviation of a random variable
Oct
17
awarded  Critic
Oct
16
comment Minimum of set $\{\frac{m}{n} + \frac{4n}{m}\}$
Hint: Can $(2n-m)^2$ be negative?