Parth Kohli
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 Apr19 revised With the binomial expansion of $(3+x)^4$ express $(3 - \sqrt 2)^4$ in the form of $p+q\sqrt 2$ rolled back to a previous revision Apr19 answered With the binomial expansion of $(3+x)^4$ express $(3 - \sqrt 2)^4$ in the form of $p+q\sqrt 2$ Apr19 comment With the binomial expansion of $(3+x)^4$ express $(3 - \sqrt 2)^4$ in the form of $p+q\sqrt 2$ forgetting $\binom{4}{k}$? Apr19 answered Derivative of $\sin(e^{-x})$ Apr14 accepted Factoring a long expression in the form $(a+b)^3 + (c - b)^3 - (c+b)^3$ Apr14 comment Factoring a long expression in the form $(a+b)^3 + (c - b)^3 - (c+b)^3$ Nice alternative. Thanks. Apr14 comment Factoring a long expression in the form $(a+b)^3 + (c - b)^3 - (c+b)^3$ @Easy wow, that is epic! Gotcha! Apr14 comment Factoring a long expression in the form $(a+b)^3 + (c - b)^3 - (c+b)^3$ $= -(b+a)(3c^2 - 3bc + b^2 + ac - ba + 2ac + a^2)$ Apr14 comment Factoring a long expression in the form $(a+b)^3 + (c - b)^3 - (c+b)^3$ @Jay Ah, I didn't notice that. Apr14 revised Factoring a long expression in the form $(a+b)^3 + (c - b)^3 - (c+b)^3$ deleted 1 characters in body; edited title Apr14 comment Factoring a long expression in the form $(a+b)^3 + (c - b)^3 - (c+b)^3$ $(c - b)^3 - (a + b)^3 = \left(c - a - 2b\right)\left(c^2 - 2cb + ac - ba + bc + a^2 + 2ab + b^2 \right)$ Is that correct? Apr14 asked Factoring a long expression in the form $(a+b)^3 + (c - b)^3 - (c+b)^3$ Apr13 accepted $x = \sqrt[3]{3} + \frac{1}{\sqrt[3]{3}}$, what is $3x^3 - 9x$? Apr13 comment $x = \sqrt[3]{3} + \frac{1}{\sqrt[3]{3}}$, what is $3x^3 - 9x$? Ah, so $3x^3 = 10 + 9x$ and I want to get the value of $3x^3 - 9x$, which gives me $10 + 9x - 9x = 10$. Great solution! Apr13 asked $x = \sqrt[3]{3} + \frac{1}{\sqrt[3]{3}}$, what is $3x^3 - 9x$? Apr12 revised The inverse function of $e^{x^2}$ added 198 characters in body Apr12 comment The inverse function of $e^{x^2}$ Brian is right as always. I have a tendency to neglect things. Apr12 answered The inverse function of $e^{x^2}$ Apr12 comment Mathematical Expressions; School Homework Err... do you know about the distributive property? Apr12 comment Mathematical Expressions; School Homework No, I have shown you that it is $7$ step-by-step.