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I was born to answer lhfs.


Apr
19
comment With the binomial expansion of $ (3+x)^4$ express $(3 - \sqrt 2)^4$ in the form of $p+q\sqrt 2$
@jack $[(3 - \sqrt{2})^2]^2 = [11 - 6\sqrt2]^2$ because $11 - 6\sqrt2 = (3 - \sqrt{2})^2$
Apr
19
revised With the binomial expansion of $ (3+x)^4$ express $(3 - \sqrt 2)^4$ in the form of $p+q\sqrt 2$
rolled back to a previous revision
Apr
19
answered With the binomial expansion of $ (3+x)^4$ express $(3 - \sqrt 2)^4$ in the form of $p+q\sqrt 2$
Apr
19
comment With the binomial expansion of $ (3+x)^4$ express $(3 - \sqrt 2)^4$ in the form of $p+q\sqrt 2$
forgetting $\binom{4}{k}$?
Apr
19
answered Derivative of $\sin(e^{-x})$
Apr
14
accepted Factoring a long expression in the form $(a+b)^3 + (c - b)^3 - (c+b)^3$
Apr
14
comment Factoring a long expression in the form $(a+b)^3 + (c - b)^3 - (c+b)^3$
Nice alternative. Thanks.
Apr
14
comment Factoring a long expression in the form $(a+b)^3 + (c - b)^3 - (c+b)^3$
@Easy wow, that is epic! Gotcha!
Apr
14
comment Factoring a long expression in the form $(a+b)^3 + (c - b)^3 - (c+b)^3$
$= -(b+a)(3c^2 - 3bc + b^2 + ac - ba + 2ac + a^2)$
Apr
14
comment Factoring a long expression in the form $(a+b)^3 + (c - b)^3 - (c+b)^3$
@Jay Ah, I didn't notice that.
Apr
14
revised Factoring a long expression in the form $(a+b)^3 + (c - b)^3 - (c+b)^3$
deleted 1 characters in body; edited title
Apr
14
comment Factoring a long expression in the form $(a+b)^3 + (c - b)^3 - (c+b)^3$
$(c - b)^3 - (a + b)^3 = \left(c - a - 2b\right)\left(c^2 - 2cb + ac - ba + bc + a^2 + 2ab + b^2 \right)$ Is that correct?
Apr
14
asked Factoring a long expression in the form $(a+b)^3 + (c - b)^3 - (c+b)^3$
Apr
13
accepted $x = \sqrt[3]{3} + \frac{1}{\sqrt[3]{3}}$, what is $3x^3 - 9x$?
Apr
13
comment $x = \sqrt[3]{3} + \frac{1}{\sqrt[3]{3}}$, what is $3x^3 - 9x$?
Ah, so $3x^3 = 10 + 9x$ and I want to get the value of $3x^3 - 9x$, which gives me $10 + 9x - 9x = 10$. Great solution!
Apr
13
asked $x = \sqrt[3]{3} + \frac{1}{\sqrt[3]{3}}$, what is $3x^3 - 9x$?
Apr
12
revised The inverse function of $e^{x^2}$
added 198 characters in body
Apr
12
comment The inverse function of $e^{x^2}$
Brian is right as always. I have a tendency to neglect things.
Apr
12
answered The inverse function of $e^{x^2}$
Apr
12
comment Mathematical Expressions; School Homework
Err... do you know about the distributive property?